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anonymous
 5 years ago
factor: w^6729
anonymous
 5 years ago
factor: w^6729

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you look at this as the difference of two squares you would get. (w^3 + 27)(w3  27) Now you have the sum and the difference of two cubes There are formulas for this. (ab)^3 = (ab)(a^2 + ab + b^2) (a+b)^3 = (a+b)(a^2  ab + b^2) so in this case replace a with "w" and b with "3" (w^3 + 27) = (w + 3)(w^2  3w + 9) (w^3  27) = (w3)(w^2 + 3w + 9) so the final answer is the product of those two answers (w + 3)(w  3)(w^2  3w + 9)(w^2 + 3w + 9)
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