LaddiusMaximus
  • LaddiusMaximus
cscx-cotxcosx=sinx im a little lost.
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

LaddiusMaximus
  • LaddiusMaximus
cscx-cotxcosx=sinx im a little lost.
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

amistre64
  • amistre64
identities... get everything in terms of "sin" and "cos" is usually a good strategy.
amistre64
  • amistre64
1/sin - (cos/sin)(cos) = sin
amistre64
  • amistre64
1 - cos^2 -------- = sin sin

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
remember that: sin^2 + cos^2 = 1 and sin^2 = 1 - cos^2
amistre64
  • amistre64
sin^2 ----- = sin sin sin=sin
LaddiusMaximus
  • LaddiusMaximus
I had got so far as 1/sinx - cosx/sinx(cosx)
amistre64
  • amistre64
you were doing good :) what stumped ya?
LaddiusMaximus
  • LaddiusMaximus
I didnt know what to do after that. Im using a program called ALEKS to do my homework and its less than helpful.
amistre64
  • amistre64
lol .... I always did homework with a pencil and paper. Back in my day that was considered prime property :)
LaddiusMaximus
  • LaddiusMaximus
well im using the paper too. okay 1-sinx - cosx/sinx then what? I already have a common denominator, so I subtract cosx from 1?
amistre64
  • amistre64
let me write it out: sin - sin^2 - cos -------------- ??? is this what you have sin
amistre64
  • amistre64
what is the original equation?
LaddiusMaximus
  • LaddiusMaximus
cscx-cotxcosx=sinx
amistre64
  • amistre64
1 - cos cos 1 - cos^2 -- --- --- = -- ----- sin sin 1 sin sin
amistre64
  • amistre64
1 - cos^2 sin^2 sin -------- = ----- = --- sin sin 1
LaddiusMaximus
  • LaddiusMaximus
gotcha. I didnt think to put the cosx over one. it makes more sense now. thank you
amistre64
  • amistre64
happy to oblige :)
LaddiusMaximus
  • LaddiusMaximus
okay new question

Looking for something else?

Not the answer you are looking for? Search for more explanations.