LaddiusMaximus
  • LaddiusMaximus
cscx-cotxcosx=sinx im a little lost.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
identities... get everything in terms of "sin" and "cos" is usually a good strategy.
amistre64
  • amistre64
1/sin - (cos/sin)(cos) = sin
amistre64
  • amistre64
1 - cos^2 -------- = sin sin

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amistre64
  • amistre64
remember that: sin^2 + cos^2 = 1 and sin^2 = 1 - cos^2
amistre64
  • amistre64
sin^2 ----- = sin sin sin=sin
LaddiusMaximus
  • LaddiusMaximus
I had got so far as 1/sinx - cosx/sinx(cosx)
amistre64
  • amistre64
you were doing good :) what stumped ya?
LaddiusMaximus
  • LaddiusMaximus
I didnt know what to do after that. Im using a program called ALEKS to do my homework and its less than helpful.
amistre64
  • amistre64
lol .... I always did homework with a pencil and paper. Back in my day that was considered prime property :)
LaddiusMaximus
  • LaddiusMaximus
well im using the paper too. okay 1-sinx - cosx/sinx then what? I already have a common denominator, so I subtract cosx from 1?
amistre64
  • amistre64
let me write it out: sin - sin^2 - cos -------------- ??? is this what you have sin
amistre64
  • amistre64
what is the original equation?
LaddiusMaximus
  • LaddiusMaximus
cscx-cotxcosx=sinx
amistre64
  • amistre64
1 - cos cos 1 - cos^2 -- --- --- = -- ----- sin sin 1 sin sin
amistre64
  • amistre64
1 - cos^2 sin^2 sin -------- = ----- = --- sin sin 1
LaddiusMaximus
  • LaddiusMaximus
gotcha. I didnt think to put the cosx over one. it makes more sense now. thank you
amistre64
  • amistre64
happy to oblige :)
LaddiusMaximus
  • LaddiusMaximus
okay new question

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