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LaddiusMaximus

  • 5 years ago

cscx-cotxcosx=sinx im a little lost.

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  1. amistre64
    • 5 years ago
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    identities... get everything in terms of "sin" and "cos" is usually a good strategy.

  2. amistre64
    • 5 years ago
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    1/sin - (cos/sin)(cos) = sin

  3. amistre64
    • 5 years ago
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    1 - cos^2 -------- = sin sin

  4. amistre64
    • 5 years ago
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    remember that: sin^2 + cos^2 = 1 and sin^2 = 1 - cos^2

  5. amistre64
    • 5 years ago
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    sin^2 ----- = sin sin sin=sin

  6. LaddiusMaximus
    • 5 years ago
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    I had got so far as 1/sinx - cosx/sinx(cosx)

  7. amistre64
    • 5 years ago
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    you were doing good :) what stumped ya?

  8. LaddiusMaximus
    • 5 years ago
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    I didnt know what to do after that. Im using a program called ALEKS to do my homework and its less than helpful.

  9. amistre64
    • 5 years ago
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    lol .... I always did homework with a pencil and paper. Back in my day that was considered prime property :)

  10. LaddiusMaximus
    • 5 years ago
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    well im using the paper too. okay 1-sinx - cosx/sinx then what? I already have a common denominator, so I subtract cosx from 1?

  11. amistre64
    • 5 years ago
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    let me write it out: sin - sin^2 - cos -------------- ??? is this what you have sin

  12. amistre64
    • 5 years ago
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    what is the original equation?

  13. LaddiusMaximus
    • 5 years ago
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    cscx-cotxcosx=sinx

  14. amistre64
    • 5 years ago
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    1 - cos cos 1 - cos^2 -- --- --- = -- ----- sin sin 1 sin sin

  15. amistre64
    • 5 years ago
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    1 - cos^2 sin^2 sin -------- = ----- = --- sin sin 1

  16. LaddiusMaximus
    • 5 years ago
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    gotcha. I didnt think to put the cosx over one. it makes more sense now. thank you

  17. amistre64
    • 5 years ago
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    happy to oblige :)

  18. LaddiusMaximus
    • 5 years ago
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    okay new question

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