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it should "post" when you hit "post" .....

I guess

cos - 1 sin
----- --- = --- is this the equation?
1-sin cos cos

yes

would algebra be the first step? common denominators?

give it a shot :)

I thought at first using the reciprocal identity for the 1/cos

okay now I have sin^2x/1-sinxcosx

which then becomes sinx/1-cosx

thinking......(12% loaded)

thinking done... got it :)

get like denoms is good; multiply cos/(1-sin) by (cos/cos) to get what?

and 1/cos get multiplied by (1-sin)/(1-sin) to get??

cos^2 - (1-sin)
------------ right?
cos(1-sin)

you follow that alright?

yeah but I ended up with cos^2x-1/1-sinxcosx

then sin^2x/1-sinxcosx

the bottom aint 1-sincos; its cos(1-sin)

cos cos - (1-sin)
-------- ------- right??
cos(1-sin) cos(1-sin)

to get like denoms; you need to multiply each side by a convenient form of (1)

cos/cos = 1 AND (1-sin)/(1-sin) = 1

ohhhh duh

lol ..... mathmatikers are tricky like that :)

then I start canceling out like numbers right?

there some manipulations first.

the bottom is good; so play with the top.

so cosx cosx - (1-sinx) becomes cos^2x -(1-sinx)

good; now what multiply out the -(1-sin). what do we get?

1+sinx

good; and how can we play with cos^2 to make it in terms of "sin"? what does cos^2 =?

sin^2x

pythagorean identity?

our top becomes what with this information?

1-sin^2x-1+sinx

but I thought -(1-sinx) would become -1+sinx - times one is -1 and - times -sinx would become +sinx

lol. now I'm lost ._.

you know what.... YOU are correct. I was wrong....
carry on please :)

who?

Laddi was right. And im glad Laddi caught it; have confidence in yourself :)

sorry for the wrong answer laddi!

1-sin^2-1+sin
what can we do with this?

replace 1-sin^2 with cose^2

sst; only if we wanna work backwards... lets try to work forwards :)

but why?

does it become sinx?

lets rewrite it this way:
1-1+sin-sin^2
now what do we do?

well 1-1 becomes 0, so sin-sin^2 is left.

think of the top as: x-x^2 if it helps

sinx can factor out 1-sinx

why don't you just flip cos/1-sin so it will be -(1-sin)/cos?

no ofcourse not it's equal to -x/2 ^^

wait, I get what you mean now ^^"

wait a minute how did (1-sin) get up top? I had sinx+sin^2x

lol .... at least one of us does :)

see, you flipped it!

I knew it

we had:
1-1+sin-sin^2 = sin-sin^2 = sin(1-sin)

find common denominator which you guys did! Good! [ (cosx)^2-1]/[(1-sin(x))(cosx)]

Now 1=(cosx)^2+(sinx)^2

Replace 1 with that

The (cosx)^2 cancel out

there's still more? I thought the question was answered

The nemerator has -(sinx)^2+sinx

ok confusion. 1-sin^2x-1+sinx becomes what?

myin; your equation is skewed look at what you posted again :)

You can factor out a (sinx) leaving with sinx(-sinx+1)

sin^2x+sinx

Laddi: (-sin^2) + sin dont forget you (-)

You can do a cancellation leaving you with the desired reult

1 (-)sin^2 (-)1 (+)sin becomes:
(-)sin^2 (+)sin

okay, then what?

Factor out what they have in common which is a sinx

then we factor out a (+sin) to get:
sin(1-sin) correct?

okay so -sinx is left on top?

The numerator gives you sinx(-sinx+1)

no sinx(sinx - 1)

wait a minute. okay right now I have -sin^2x +sinx/cosx(1-sinx)

No ss the sinx is negative and the 1 is postive

good Laddi;

so -sin^2x factors out the +sinx?

yes...

so im left with -sinx/cosx(1-sinx)

You should be left with [(sinx(-sinx+1)]/[cosx(1-sinx)]

Does anything cancel?

(-sin^2 +sin)/cos(1-sin) becomes...
sin(1-sin) / cos(1-sin)

I'll just wacth ^-^

-sinx+1=1-sinx So that part in you numerator cancels out with that part in the denominator

Laddi:
Does -sin^2 + sin = sin(1-sin) ???

-sin(sin -1)

I didnt think it did.

or sin(-sin + 1) = sin (1-sin)

^^

lol, yes u were right

now im confused.

Laddi: lets figure this part out:
-sin^2 + sin: can we rewrite this as:
sin - sin^2?

get it? ^^

sst: one step at a time :)

sorry ^^"

okay I got that part.

awesome! amistre continue :)

okay then it becomes 1-sinx?

that sinx doesnt go away. one takes it place when it factors a sinx out of sin^2x

Laddi; yes

so sin-sin^2x becomes 1-sinx

it becomes.... pull a sin out...... sin(1-sin) right?

Trig identities are the BEST!

wait what?

i thought sinx-sin^2x becomes 1-sinx?

laddi, 4 = 2 x 2 right?
let's say we have 4 - 2x, factor what will the answer be?

it becomes sinx(1-sinx)

2(2-x) right?

imagine the 2 as sinx :)

so instead of 4- 2x we have = 2(2-x)
sin^2 - sin = sin(1-sin)
ta da!

same story ^^

it is basic algebra... thats all

havent taken basic algebra in over 10yrs

did u get my example? :)

lol .... it was 20 years for me when I went back to college..

laddi did you understand my example? with the 2 thingy?

yeah its hard to conceptualize right now.

oh wow i like that word. is that a word conceptualize?

try to recall this:
5a- a^2 = a(5-a)

hmm I get it now that Im looking at it on paper.
sheesh

^_^

paper helps too :)

and a marker

and some juice

and a nap too

good luck laddi hope u got it now :)

nap would be nice :)

More Math!

so when you take a sin away it becomes 1?

You aren't really taking it away. That 1 is being multiplied by that sinx

so its more of a standard? 5(a-a^2) becomes 5a-5a^2?