A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
I have the problem 27^4z=9^(z+1) I don't want the answer, just help figuring out the proper way to simplify both sides of the equation so I can add the exponents. I know the bases will be the same, 3^(whatever power)
anonymous
 5 years ago
I have the problem 27^4z=9^(z+1) I don't want the answer, just help figuring out the proper way to simplify both sides of the equation so I can add the exponents. I know the bases will be the same, 3^(whatever power)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have gotten as far as 3^3(4z)=3^2(z+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know what to do with the exponents, whether I should add them, multiply them, divide them or whatever else. I am not familiar with the log function yet. The chapter the homework is in is on exponential functions, so trying to do it that way first.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.027^4z=9^(z+1) log(27^4z) = log(9^(z+1)) 4z (log(27)) = (z+1) (log(9)) get like terms together now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I already have the bases, I just need to know what to do with the exponents. Again, trying to do this without a calculator. I want to understand the process before I rely on a calculator for the answers

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0exponents an logs are hand in hand. they are inverses of each other and you need logs to work exponents with a variable in them

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you can "remember" exponents if you want and try to recall what is what... but it is harder

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04z (log(27)) = (z+1) (log(9)) 4z.3log (3)= (z+1)2log (3) 12z=2z+2 z=1/5

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the relation is this: B^x = y x = logB(y)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0As for exponent rules: 3^(2^x) = 3^(2x). when exponents have an exponent; the exponents multiply together

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THAT is what I needed :D The exponent rule.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got it right easily that time. Just didn't know what to do with it, thank you very much d:D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0{I have gotten as far as 3^3(4z)=3^2(z+1)}. when you got this , why are you mess with log.. just compare exponents of 3 n get the result

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0easy when you can "know" the base..
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.