(square root of 2)^(x+4)=4^x I just want to know how to get the bases to be the same. Do you square both sides, or do I "arrange" the right side of the equation to get the bases to be the same?

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(square root of 2)^(x+4)=4^x I just want to know how to get the bases to be the same. Do you square both sides, or do I "arrange" the right side of the equation to get the bases to be the same?

Mathematics
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sqrt(2)^(x+4) = 4^x square both sides to get rid of the sqrt sign
[sqrt(2)^(x+4)]^2 = [sqrt(2)^2]^(x+4) [4^x]^2 = [4^2]^x
we get: 2^(x+4) = 4^2x

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Other answers:

I get x=4/3
I wrote both sides as base sqrt(2)
4=(sqrt(2))^4
(sqrt(2))^(x+4)=(sqrt(2))^(4x)
so x+4=4x

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