A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
what is the range for the following y=3/x+2? and why?
anonymous
 5 years ago
what is the range for the following y=3/x+2? and why?

This Question is Closed

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0Since it is one to one. you can find the inverse and find the domain of the inverse. The domain of the inverse is the range of y=3/x+2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my textbook says that the range can be anything except zero. i don't understand why?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0You are talking about the domain of this function. x cannot be zero because you cannot divide by 0. The domain of y is therefore (inf,0) U (0,inf)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is too complex for me to understand, i havenot learnt about infinity yet. i just want to know why the range can not be zero. an the domain can be zero , however it can not be negatvie 2 . becauause it will make the denominator zero. i just do not know why my textbook said i can not have y as zero

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i have to go I'm sorry but the domain of this function is (inf,0)U(0,inf) and the range is (inf,2)U(2,inf) and I found this because I found the inverse and the domain of the inverse is the range of y

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0I requested some help for you hopefully someone will be in a second

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i still do not get it, please answer
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.