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anonymous
 5 years ago
does anyone know how to gernerate the equation of a circle with endpoints of diameter at (3,5) and (7,11)
anonymous
 5 years ago
does anyone know how to gernerate the equation of a circle with endpoints of diameter at (3,5) and (7,11)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya. just use your equation of a circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i got (x2)^2 + (y8)^2= and then what?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x+3)(x7) + (y5)(y11) = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoa thanks dude i thought u didn't like me lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry , if you felt i that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0equation of any circle if the end points of its diameter are (a,b) and (p,q) is (xa)(xp) + (yb)(yq) =0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you try to help with mine?
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