## anonymous 5 years ago How do I do square root y^3 * cubed square root y^2? I am totally confused with this problem.

1. anonymous

is this $y^{3}\sqrt[3]{y^2}$ you are working with?

2. anonymous

under a square root sign?

3. anonymous

If I'm reading you right, then your equation would look like y^(3/2)*y^(2/3). With same bases, you would add your exponents, so 3/2+2/3=13/6. Your answer is y^13/6, which you can simplify.

4. anonymous

Remember that roots are just the base raised to 1 over whatever you are rooting to. For example, the square root of y is the same as y^(1/2), and the cube root is y^(1/3). Prove this to yourself on a calculator with y as any number. If your base already has an exponent, that exponent becomes the numerator. So square root of y^3 is y^(3/2) and cube root of y^2 is y^(2/3).

5. anonymous

Mfang its not an equation. Its radicals.

6. anonymous

Daomowon its $\sqrt{y ^{3}}$

7. anonymous

thats not what i typed...omg going crazy over this problem

8. anonymous

its that prob X sqrt y^3

9. anonymous

there is a sqrt sign with the y^3

10. anonymous

mfang Im sorry your correct

11. anonymous

no need to worry, whatever I just typed didn't come up but $y^3 = y^2*y$, then