anonymous
  • anonymous
Need a little help with this formula. y=mx+b. x1=2, y1=-3, m=-1/5. I have so far y=-1/5x?? what is the rest of it?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
y+3=(-1/5)(x-2)
anonymous
  • anonymous
Expand y=mx+b to (y-k)=m(x-h) where (h,k) is a point. From the given information, you know x=2 and y=-3, so (h,k) is (2, -3). Check signs when plugging in.
anonymous
  • anonymous
Afterwards, distribute your (-1/5) into (x-2), subtract 3 on both sides, and viola. :)

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anonymous
  • anonymous
I got the y+3=-1/5(x-2). So subtract 3 form both sides is y=-1/5x+1?
anonymous
  • anonymous
Watch the parenthesis. You're going to get y=(-1/5)x+2/5-3. y=-x/5-13.5 is your final equation.
anonymous
  • anonymous
I thought that the -1/5x would not change. I am lost now.
anonymous
  • anonymous
I gave that as an answer but it says it is wrong.
anonymous
  • anonymous
ok, so here's what happened. (-1/5)x means (-1/5) times x, which is the same as putting x over a -5. (-1/5)x=-x/5. I'd review a little over notation, if I were you. :)
anonymous
  • anonymous
y=-x/5-13/5, I meant.
anonymous
  • anonymous
Ok got it. that worked thank you.

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