which one is the smallest? a. 3/7 b. 1/3 c. 5/6 or d. 9/14 i know the answer is b. 1/3 but how do i get the answer? to all of them? what is the process?

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which one is the smallest? a. 3/7 b. 1/3 c. 5/6 or d. 9/14 i know the answer is b. 1/3 but how do i get the answer? to all of them? what is the process?

Mathematics
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Get them all to where the denominators are the same. Your least common denominator is 42. a. 18/42 b. 14/42 c. 35/42 d. 27/42 From this, you can easily tell that b is the smallest. :)
okay so would i do this to every problem i come across with that is just like this one?
Do it for each. You find your least common denominator by checking the factors in your denominator numbers. Let me explain: 7 is a prime number, and is the only factor you need to consider for a. Likewise, 3 is what you need out of b. 6 has factors of 2 and 3, but there's already a 3, so you just need the 2 from there. 14 is 2*7, and both are already represented. So the least common denominator of 7, 3, 6, and 14 is 7*3*2, or 42.

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As another example, the least common denominator for something like 1/8 and 1/6 would be something over 24 since 8 has 2 and 4 and 6 has 2 and 3. Disregard repeated factors (the 2, in this case) and multiply the rest of them together. So 2*4*3=24. Don't forget to scale up the numerators! 1/8 and 1/6 become 3/24 and 4/24, respectively.

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