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anonymous
 5 years ago
How do we do this Solve 276(x10)>3x+26
anonymous
 5 years ago
How do we do this Solve 276(x10)>3x+26

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Set the inequality to an equality and solve for x. This will determine the boundary of your intervals. You then take a test point from each interval to see if the inequality is satisfied in that region. If the test point works, all xvalues in that region form part of your solution. If the test point doesn't work, the region isn't included.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So\[276x+60=3x+26\]yields\[2726+60=3x+6x \rightarrow 61=3x\]that is,\[x=\frac{61}{3}\]is the boundary point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You only have one point, so the number line will be broken into two regions: all those x such that x<61/3 and all those x such that x>61/3 (note 61/3 is not included since you have a strict inequality).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Choose x=0. Then\[276(010)>^?3(0)+26 \rightarrow 87>^?26\] True. So x<61/3 is one region.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For completeness check the other: x>61/3. Choose 100. Then\[276(10010)>^?3(100)+26 \rightarrow 513>^?274\]False. So x>61/3 is not a solution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your solution is all x less than 61/3.
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