## anonymous 5 years ago what does -1/2(tan(x) limit -pi/3to pi/3 equal to

1. anonymous

i am having trouble understanding your statement. Can you state the problem as a sentence?

2. anonymous

the problem is 1/2 (tan x) the limit is -pi/3 to pi/3 (you have to plug these values into x) i didn't get the right answer, i want to c what the problem is

3. anonymous

is this calculus?

4. anonymous

yes

5. anonymous

$\lim_{x\rightarrow -\frac{\pi}{3}}\frac{1}{2}\tan x$

6. anonymous

is that the question?

7. anonymous

no i found the integral of the problem which came out to be (1/2tanx) the limit is -pi/3 to pi/3. could u plug it in and tell me what u get

8. anonymous

okay

9. anonymous

you should state your question more clearly

10. anonymous

$\frac{\sqrt{3}}{2}$

11. anonymous

how did u get a positive number

12. anonymous

was the definite integral $\int^{\frac{\pi}{3}}_{-\frac{\pi}{3}}\frac{1}{2} \sec^2 x dx$

13. anonymous

at any rate $\frac{1}{2}\left\{\tan(\frac{\pi}{3})-\tan(-\frac{\pi}{3})\right\}$

14. anonymous

$=\frac{1}{2}\left\{\frac{\sqrt{3}}{2}-(-\frac{\sqrt{3}}{2})\right\}$

15. anonymous

$=\frac{1}{2}\frac{\sqrt{3}}{4}$

16. anonymous

sorry that was wrong

17. anonymous

latex error

18. anonymous

$\frac{1}{2} 2\sqrt{3}$

19. anonymous

did it again

20. anonymous

so -pi/3= sqrt3/2

21. anonymous

no

22. anonymous

i mean tan of that angle

23. anonymous

but $\tan(-\frac{\pi}{3})=-\frac{\sqrt{3}}{2}$

24. anonymous

got ya, but no

25. anonymous

man

26. anonymous

tangent is negative in the fourth quadrant

27. anonymous

look at the tangent graph or the unit circle to comfirm

28. anonymous

k ty