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anonymous

  • 5 years ago

what does -1/2(tan(x) limit -pi/3to pi/3 equal to

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  1. anonymous
    • 5 years ago
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    i am having trouble understanding your statement. Can you state the problem as a sentence?

  2. anonymous
    • 5 years ago
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    the problem is 1/2 (tan x) the limit is -pi/3 to pi/3 (you have to plug these values into x) i didn't get the right answer, i want to c what the problem is

  3. anonymous
    • 5 years ago
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    is this calculus?

  4. anonymous
    • 5 years ago
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    yes

  5. anonymous
    • 5 years ago
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    \[\lim_{x\rightarrow -\frac{\pi}{3}}\frac{1}{2}\tan x\]

  6. anonymous
    • 5 years ago
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    is that the question?

  7. anonymous
    • 5 years ago
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    no i found the integral of the problem which came out to be (1/2tanx) the limit is -pi/3 to pi/3. could u plug it in and tell me what u get

  8. anonymous
    • 5 years ago
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    okay

  9. anonymous
    • 5 years ago
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    you should state your question more clearly

  10. anonymous
    • 5 years ago
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    \[\frac{\sqrt{3}}{2}\]

  11. anonymous
    • 5 years ago
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    how did u get a positive number

  12. anonymous
    • 5 years ago
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    was the definite integral \[\int^{\frac{\pi}{3}}_{-\frac{\pi}{3}}\frac{1}{2} \sec^2 x dx\]

  13. anonymous
    • 5 years ago
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    at any rate \[\frac{1}{2}\left\{\tan(\frac{\pi}{3})-\tan(-\frac{\pi}{3})\right\}\]

  14. anonymous
    • 5 years ago
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    \[=\frac{1}{2}\left\{\frac{\sqrt{3}}{2}-(-\frac{\sqrt{3}}{2})\right\}\]

  15. anonymous
    • 5 years ago
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    \[=\frac{1}{2}\frac{\sqrt{3}}{4}\]

  16. anonymous
    • 5 years ago
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    sorry that was wrong

  17. anonymous
    • 5 years ago
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    latex error

  18. anonymous
    • 5 years ago
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    \[\frac{1}{2} 2\sqrt{3}\]

  19. anonymous
    • 5 years ago
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    did it again

  20. anonymous
    • 5 years ago
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    so -pi/3= sqrt3/2

  21. anonymous
    • 5 years ago
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    no

  22. anonymous
    • 5 years ago
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    i mean tan of that angle

  23. anonymous
    • 5 years ago
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    but \[\tan(-\frac{\pi}{3})=-\frac{\sqrt{3}}{2}\]

  24. anonymous
    • 5 years ago
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    got ya, but no

  25. anonymous
    • 5 years ago
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    man

  26. anonymous
    • 5 years ago
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    tangent is negative in the fourth quadrant

  27. anonymous
    • 5 years ago
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    look at the tangent graph or the unit circle to comfirm

  28. anonymous
    • 5 years ago
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    k ty

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