find three consecutive multiples of 15 such that twice their sum is 360

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find three consecutive multiples of 15 such that twice their sum is 360

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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so we know that those 3 consecutive numbers equal 180, so those 3 numbers are 45, 60, and 75
yeah i know i dont know how to explain
If 15x is the first number, then the other two are 15(x+1) and 15(x+2)....then 2[15x + 15(x+1) + 15(x+2)] =360....solve and u'll get x=3....sub into the expressions repr the three numbers...u'll get 45, 60 and 75

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