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anonymous

  • 5 years ago

find three consecutive multiples of 15 such that twice their sum is 360

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  1. NY,NY
    • 5 years ago
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    so we know that those 3 consecutive numbers equal 180, so those 3 numbers are 45, 60, and 75

  2. NY,NY
    • 5 years ago
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    yeah i know i dont know how to explain

  3. anonymous
    • 5 years ago
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    If 15x is the first number, then the other two are 15(x+1) and 15(x+2)....then 2[15x + 15(x+1) + 15(x+2)] =360....solve and u'll get x=3....sub into the expressions repr the three numbers...u'll get 45, 60 and 75

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