looking for help finding factors that when multipied equal 430 but when added equal 76. Can anyone help?

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looking for help finding factors that when multipied equal 430 but when added equal 76. Can anyone help?

Mathematics
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Are you sure it isn't 420? If it is, it is 6 and 70
no unfortunely it is 430.
x*y = 430 x+y = 76

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x*y = 430 y = 76-x
x*(76-x)=430 y = 76-x
what do u mean factors? do u mean just 2 numbers?
76x-x^2 = 430 y = 76-x
like a . b = 430 and then a+b=76
OMG this place crashes too much so: -x^2 +76x - 430 = 0
let's see if discriminant works: D = 76^2 - 4 * (-1) * (-430) = 5776 - 1720 = 4056
Uhmm.. r us sure the problem is right? Because radical D is 63.68673331, etc..
i'm still thinking that blexting was right.. the question is supposed to have a 420.. Nobody in their right mind would assign a problem with decimals.. well unless ur dealin with physics
ok maybe i went about this the wrong way. i am look for an answer for -2x squared+76x+ 430. supposed to factor by grouping i think. trying to figure it out might have messed u
oops mean up*
I think this way it makes sense.. and if u can't factor use quadratics. it's much easier
-2x^2 + 76x + 430 = 0 by the way is it + 430 or - 430?
D = 76^2 - 4 * (-2) * 430 = 5776 + 3440 = 9216
x1 = (-76-sqrt(9216))/(2*(-2)) = (-76 - 96)/-4 = 43
x2 = (-76+sqrt(9216))/(2*(-2)) = (-76 + 96)/-4 = 20/-4 = -5
So to factor ur equation you would have: (x-43)(x+5)=0
Please click on become a fan if I helped, I really want to get to the next level!! Thanks =)
First of all if -2x^2 + 76x + 430 = 0 is the equation Then the first thing you do is to factor out the -2 (common factor) -2(x^2 - 38x - 215) = 0 Then you would be looking for factors of 215 that subtract to get 38 Which would be 43 and 5 So it would factor into -2(x - 43)(x + 5) = 0

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