Working on trig identities and came across a problem:
(1-sin t)^2/ cos^2 t = 1-sin t/ 1+ sin t
This is as far as I got: cos ^2 t/ cos ^2 t=1-sin t/ 1+ sin t
Help please :)

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- anonymous

First of all the most important identity in trig is sin^2x + cos^2x = 1 if you solve this for cos^2x you would subtract sin^2x from both sides so ... cos ^2x = 1 - sin^2x
After that you would substitute in the original equation. So where you see cos^2t on the bottom you would replace it with 1 - sin^2t
Secondly.. You would write the top as (1 - sint)(1 - sint) and the bottom would factor because it is the difference of two square.. So the bottom would be (1 + sint)(1 - sint). The (1 - sint) would cancel from the top and bottom and would you be left with 1 - sint / 1 + sint

- anonymous

Thank you so very much for helping me!! I truly appreciate it! It's like a lightbulb went off in my head, Thank You!!!!

- anonymous

You are welcome... You will use sin^2x + cos^2x = 1 a bunch....

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- anonymous

Your certainly right about that, I appreciate the help. Thanks for the advice!

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