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This is like the one I did earlier for you. The goal is to get n by itself in the middle.. What number would you get rid of first in the middle?
can we get rid of 1
Yes.. Sorry, I was helping someone else. So you subtract one from all three sides. 3 -1 > 1-1-n/2> -2-1
Which is 2 > -n/2 > -3
Then what would we do?
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so after we subtract do we divide?? and get 'n' by itself
To get rid of the 2 on the bottom... it says /2 so we do the opposite which is multiply by 2. We will do this this way and then we will have one more step.
So take all three * 2 we would get 2 * 3 > 2* -n/2 > -3 * 2 which is
6 > -n > -6 can you see that the 2 and the /2 on the bottom cancel? Let me know when you get this and then we will do one more step.
now are we fliping the signes?
Well. yes but you still have to get rid of the - sign so you take the opposite of all three sides.. another way is to multiply all three by -1 they are both the same idea. and YES YOU FLIP THE SIGNS.. VERY GOOD
so you get -6 < n < 6
You could have multiplied by -2 back in the second step and flipped the sign then because you multiplied by -2... I didn't know if you could handle that step all at once.