## anonymous 5 years ago Find the oblique or (slant asymptote) of y = (5x^3 +6x^2) / (5x^2 + 4x + 5) and express your answer in the form y = mx + b, where m and b are constants

I've done oblique asyptotes years ago. Maybe I can help you out, there are several steps that you must take. 1) Check if your function is an oblique asyptote my finding the limi as x --> infinity 2) If you end up with infinity, then youhave an oblique asymptote 3) After that divide your function y/x to find m, since y = mx + b; mx = y, m = y/x. Then simplify your expression. 4) Then after finding y/x, which is the slope, subtract it from the original mx to find b , so b = (y - mx) . Remember mx = the new slope that you have found. 5) finally you have the slope + b, so you can then write the equation of the OA. Those were general steps that can help you solve any problem that has an OA, as for your question: $y = 5x^3 + 6x^2/ 5x^2 + 4x + 5$ , step number (1) divide it by x and you'll get $y = (5x^3 + 6x^2)/ x(5x^2 + 4x + 5)$ multiply x using the distributive law and you will have : $y = 5x^3 + 6x^2 /5x^3 + 4x^2 + 5x$ now find the limit of this as it goes to infinity: m = $\lim_{x \rightarrow \infty} = 5x^3/5x^3$ = 1 After that we need to find b now, we know that b = y - mx, and we have found m = 1, so m = x. Now subtract y ( the original function) from m ( which is x): $(5x^3+6x^2 / 5x^2 + 4x+ 5 ) - x$ do the simplification and you'll end up with : $5x^3+ 6x^2 - 5x^3 - 4x^2- 5x/5x^3 + 4x^2 + 5x$ = $2x^2-5x/ 5x^2 + 4x + 5$ then find the limit of that as x goes to infinity: $\lim_{x \rightarrow \infty} 2x^2/5x^2 = 2/5$ Finally write your equation in a more decent form: - m = 1 -b = 2/5 so y = x + 2/5 Done :)