- anonymous

can someone tell me how to graph this equation on my graphing calculator: 300(2+sin(4sqrt x+0.15)) for 0

Mathematics
- schrodinger

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- anonymous

You just do it...
What type of calculator do you have?

- anonymous

ti 83

- anonymous

Y= --> Enter: 300(2 + sin(4 sqrt(x + 0.15))
Then, to see the region from 0 Xmin = 0; Xmax = 20; Ymin = -20 Ymax = 20

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## More answers

- anonymous

Might have to change the Ymin / Ymax values - I'm just guessing :D

- anonymous

Become a fan DX

- anonymous

give me a sec and let me try it

- anonymous

what should mt table set be

- anonymous

Do you need the table? If so --> 2nd Window (for table settings)
Tbl start = 0; triangleTable (change in table) = 1 or 0.5

- anonymous

it didnt work

- anonymous

Why's that - what did you enter on the calculator?

- anonymous

Zoom out then.

- anonymous

Oh yeah, our Ymax / Ymin values are not right at all.
Make Ymax = 900 and Ymin 200

- anonymous

nothing is graping

- anonymous

Do what I said above.

- anonymous

Btw is that sqrt(x) + 0.15 or sqrt(x + 0.15)
I'm guessing it's the former.

- anonymous

hey it worked good job but why did u choose 200 and 900

- anonymous

Cause on the table it starts out over 200 and then it goes up to a max of 900 ish.

- anonymous

I have attached the graph. This is the accurate graph, and is drawn to scale

##### 1 Attachment

- anonymous

What do you open up that file with?

- anonymous

May be you couldn't open the file. Ok here it is

##### 1 Attachment

- anonymous

hey ty u for sending it over but i do not understand how to choose my max and min

- anonymous

for the y

- anonymous

Could anyone open the file?

- anonymous

yah i did i saw it ty

- anonymous

does anyone know how to choose 200 and 900

- anonymous

why it has to be 200 and 900

- anonymous

are you asking me?

- anonymous

yah

- anonymous

For that you will have to find the derivative, and equate it to zero

- anonymous

are you getting me?

- anonymous

yah . do u know how to find the integral on the calculator

- anonymous

No I don't, but I can provide you that here

- anonymous

If you wish.........

- anonymous

if u know plez show

- anonymous

Here it is attached

##### 1 Attachment

- anonymous

And I am attaching the graph in jpg format, as last time it was not openeable

##### 1 Attachment

- anonymous

yah i saw it

- anonymous

Did your problem got solved or it increased? :)

- anonymous

kind of ty

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