anonymous
  • anonymous
can someone tell me how to graph this equation on my graphing calculator: 300(2+sin(4sqrt x+0.15)) for 0
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
You just do it... What type of calculator do you have?
anonymous
  • anonymous
ti 83
anonymous
  • anonymous
Y= --> Enter: 300(2 + sin(4 sqrt(x + 0.15)) Then, to see the region from 0 Xmin = 0; Xmax = 20; Ymin = -20 Ymax = 20

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anonymous
  • anonymous
Might have to change the Ymin / Ymax values - I'm just guessing :D
anonymous
  • anonymous
Become a fan DX
anonymous
  • anonymous
give me a sec and let me try it
anonymous
  • anonymous
what should mt table set be
anonymous
  • anonymous
Do you need the table? If so --> 2nd Window (for table settings) Tbl start = 0; triangleTable (change in table) = 1 or 0.5
anonymous
  • anonymous
it didnt work
anonymous
  • anonymous
Why's that - what did you enter on the calculator?
anonymous
  • anonymous
Zoom out then.
anonymous
  • anonymous
Oh yeah, our Ymax / Ymin values are not right at all. Make Ymax = 900 and Ymin 200
anonymous
  • anonymous
nothing is graping
anonymous
  • anonymous
Do what I said above.
anonymous
  • anonymous
Btw is that sqrt(x) + 0.15 or sqrt(x + 0.15) I'm guessing it's the former.
anonymous
  • anonymous
hey it worked good job but why did u choose 200 and 900
anonymous
  • anonymous
Cause on the table it starts out over 200 and then it goes up to a max of 900 ish.
anonymous
  • anonymous
I have attached the graph. This is the accurate graph, and is drawn to scale
1 Attachment
anonymous
  • anonymous
What do you open up that file with?
anonymous
  • anonymous
May be you couldn't open the file. Ok here it is
anonymous
  • anonymous
hey ty u for sending it over but i do not understand how to choose my max and min
anonymous
  • anonymous
for the y
anonymous
  • anonymous
Could anyone open the file?
anonymous
  • anonymous
yah i did i saw it ty
anonymous
  • anonymous
does anyone know how to choose 200 and 900
anonymous
  • anonymous
why it has to be 200 and 900
anonymous
  • anonymous
are you asking me?
anonymous
  • anonymous
yah
anonymous
  • anonymous
For that you will have to find the derivative, and equate it to zero
anonymous
  • anonymous
are you getting me?
anonymous
  • anonymous
yah . do u know how to find the integral on the calculator
anonymous
  • anonymous
No I don't, but I can provide you that here
anonymous
  • anonymous
If you wish.........
anonymous
  • anonymous
if u know plez show
anonymous
  • anonymous
Here it is attached
1 Attachment
anonymous
  • anonymous
And I am attaching the graph in jpg format, as last time it was not openeable
1 Attachment
anonymous
  • anonymous
yah i saw it
anonymous
  • anonymous
Did your problem got solved or it increased? :)
anonymous
  • anonymous
kind of ty

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