Can I see someone solve, simplify the expression: (b^2+5b+6) divided by (3bc) divided by (b^2-9) divided by (6bc)

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Can I see someone solve, simplify the expression: (b^2+5b+6) divided by (3bc) divided by (b^2-9) divided by (6bc)

Mathematics
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you'll get something like this first :\[6bc ( b^2 + 5b + 6)/ 3bc(b^2-9)\]
then you can cancel the 6bc with 3bc and you'll get :\[2(b^2+5b+6)/(b^2-9) = 2(b+3)(b+2)/(b-3)(b+3) = 2(b+2)/(b-3)\]
2(b^2 + 5b + 6) / (b^2 - 9) 2(b + 3)(b + 2) / (b+3)(b-3) 2(b+2) / (b-3) (2b + 4) / (b-3)

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2(b+2)/(b-3) , sorry lol, lagging
I can just do it fast. Ego strong here. :D
lol, I was lagging =P
Got that too
Though I commend you for using the equation. And no, you still can't do it faster than me. ^_^
lol, it's not about how fast you solve it, it's about whether you did it correctly or not :) + whether you helped someone or not ^_^
It helped!
It's about beating you, sstarica, that's all it's about.
DX
SStarica said 2(b+2)/(b-3) and Supervisor said (2b+4)/(b-3) and in my study book it says the answer is 2(b+2) / (b-3) my hero.

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