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anonymous
 5 years ago
(xlny+xy) if i differentiate that with respect to y... i think i get 0
anonymous
 5 years ago
(xlny+xy) if i differentiate that with respect to y... i think i get 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you differentiate with respect to y, all you do is treat the \(x\) variable as a constant. Since \(\ln{y}\) doesn't differentiate to zero, and neither does \(y\), you shouldn't get zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the derivative of \(\ln{y}\) is \(\frac{1}{y}\), and the derivative of \(y\) is \(1\). Does that help get you moving?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0He didn't say partial derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got the answer x/y+x

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0This could be implicit differiention

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yep, that's right. Unless myininaya is right about it being implicit differentiation. Are you learning about implicit differentiation now, or partial derivatives?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0If we aren't doing partial differentiation, the answer is x'lny+x/y+x'y+x

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0Since x is a function of y

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0Have you heard of partial derivatives?
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