anonymous
  • anonymous
Question can someone perform this operation? simplify the expression: numerator (6r^2-7r-3) divided by denominator (r^2-1) divided by numerator (4r^2-12r+9) divided by denominator (r^2-1) multiply by numerator (2r^2-r-3) divided by denominator (3r^2-2r-1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Can I just give the answer out? Too much typing.
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Your question is worded a little bit strangely... When you say numerator and then the denominator, do you mean each of those are one set of terms? aka (6r^2 - 7r - 3) / (r^2 - 1) ------------------------- <--divided by (4r^2 - 12r + 9) / (r^2 - 1) ------------------------- (2r^2 - r - 3) / (3r^2 - 2r - 1)

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anonymous
  • anonymous
Yes like numerator 12 divided by denominator 2=6
amistre64
  • amistre64
Can you write this out using grouping symbols to make the question easier to read?
anonymous
  • anonymous
Yes all of the numerators are numerator but in sets like you have up top there.
amistre64
  • amistre64
For example: 4/2/2 can be taken several ways: (4/2)/2 = 2/2 = 1 4/(2/2) = 4/1 = 4 As you can see; 4 does not equal 1 so the way the problem is set up is important
anonymous
  • anonymous
Sorry, going to start it now.
anonymous
  • anonymous
(3r + 1)^ 2 * (r^2 - 1)
amistre64
  • amistre64
If you define a way to set the problem up like using "//" to be the determining division between top and bottom... that would be helpful: example: 4//2/2 = 4 4/2//2 = 1
anonymous
  • anonymous
(r+1)/(r-1)
anonymous
  • anonymous
6r^2-7r-3/r^2-1 / 4r^2-12r+9/r^2-1 times 2r^2-r-3/3r^2-2r-1
anonymous
  • anonymous
Beens that looks like the right solution, does anyone have more input?
amistre64
  • amistre64
(2r-3)(3r+1) -------- (r+1)(r-1) (2r-3)(r+1) -------------- times --------- = ? (2r-3)(2r-3) (r-1)(3r+1) ---------- (r+1)(r-1)
amistre64
  • amistre64
If so, I get: (3r+1)(2r-3)(r+1) (r+1) --------------- = ----- same as Beens (2r-3)(r-1)(3r+1) (r-1)

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