anonymous
  • anonymous
helpo with bernoulli differential equation... y'+xy=xy^2
Mathematics
jamiebookeater
  • jamiebookeater
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divanshu
  • divanshu
what help do you want ? tell full question
anonymous
  • anonymous
I need to solve using the bernoulli method of u substitution. So far I have u'=-y^(-2)y' and u=y^(-1), substitued as u'-xu=-x
anonymous
  • anonymous
y' = xy^2 - xy dy / dx = xy^2 - xy dy = (xy^2 - xy) dx dy = (x)(y^2-y) dx dy / (y^2 - y) = x dx

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anonymous
  • anonymous
Someone else continue this. :D
anonymous
  • anonymous
I realize you can solve it that way, but my prof wants us to use the bernoulli method of u substitution...
anonymous
  • anonymous
Sorry :'( Don't know

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