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anonymous
 5 years ago
helpo with bernoulli differential equation... y'+xy=xy^2
anonymous
 5 years ago
helpo with bernoulli differential equation... y'+xy=xy^2

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divanshu
 5 years ago
Best ResponseYou've already chosen the best response.0what help do you want ? tell full question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need to solve using the bernoulli method of u substitution. So far I have u'=y^(2)y' and u=y^(1), substitued as u'xu=x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y' = xy^2  xy dy / dx = xy^2  xy dy = (xy^2  xy) dx dy = (x)(y^2y) dx dy / (y^2  y) = x dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Someone else continue this. :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I realize you can solve it that way, but my prof wants us to use the bernoulli method of u substitution...
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