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anonymous

  • 5 years ago

10x^2 - 11x - 6 Factor

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  1. anonymous
    • 5 years ago
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    (5x+2)(2x-3)

  2. anonymous
    • 5 years ago
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    how did u get that?

  3. myininaya
    • 5 years ago
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    This is in the form of ax^2+bx+c where a=10, b=-11, c=-6. Find factors of a*c that add up to be b. a*c=(10)(-6)=-60. What are factors of -60 that add up to be -11

  4. anonymous
    • 5 years ago
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    im not sure

  5. myininaya
    • 5 years ago
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    -15*4=-60 and -15+4=-11

  6. myininaya
    • 5 years ago
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    So replace -11x=-15x+4x

  7. myininaya
    • 5 years ago
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    so we have 10x^2-15x+4x-6

  8. myininaya
    • 5 years ago
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    Factor by grouping

  9. myininaya
    • 5 years ago
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    What do the first two terms have in common

  10. anonymous
    • 5 years ago
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    2?

  11. anonymous
    • 5 years ago
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    this literally by observation. 10= 1*10= 2*5 factor of 6: 1*6=2*3 try mix and match the factors in form (ax+b)(cx+d) where a&c is a pair of factor 10 and b&d a pair of factor 6. and ad+bc=-11

  12. anonymous
    • 5 years ago
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    o okay

  13. myininaya
    • 5 years ago
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    You can also do trial factors like anfar if you like

  14. anonymous
    • 5 years ago
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    i also have the problem 125n^2 + 50n + 5

  15. myininaya
    • 5 years ago
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    ok so 5x(2x-3)+2(2x+3)

  16. myininaya
    • 5 years ago
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    (2x+3)(5x+2) which is what anfar got

  17. myininaya
    • 5 years ago
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    oops

  18. myininaya
    • 5 years ago
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    it was suppose to be 5x(2x-3)+2(2x-3)

  19. myininaya
    • 5 years ago
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    =(5x+2)(2x-3)

  20. myininaya
    • 5 years ago
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    now thats what anfar got

  21. anonymous
    • 5 years ago
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    for the 2nd problem: first, make the numbers smaller.note that 125,50 and 5 have common factors 5. so now u have: 5(25n^2+10n+1) then, u can try use the mix and match for the equation in the bracket.

  22. anonymous
    • 5 years ago
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    would it be 5(5n+ 2)....?

  23. anonymous
    • 5 years ago
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    no. it should be 5(5n+1)(5n+1)=5(5n+1)^2

  24. anonymous
    • 5 years ago
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    but then what happens to the 10?

  25. anonymous
    • 5 years ago
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    i put it this way: let say u have an equation in form Ax^2+Bx+C: u have to factor it in form of (ax+b)(cx+d) where: a*c=A , b*d=C and ad+bc=B

  26. anonymous
    • 5 years ago
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    okay

  27. anonymous
    • 5 years ago
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    in the 2nd case, u considering 25n^2+10n+1 so, u hav A=25, B=10 and C=1 note that 1=1*1 or -1*-1 since B is positive, u take the positive ones. so, u now have b=d=1 thus, a*c=25 and a+c=10 now, 25=25*1=5*5. 25+1 not equal to 10. so u take a=c=5. therefore u have: 5(5n+1)(5n+1)=5(5n+1)^2 as the answer. u got it?

  28. anonymous
    • 5 years ago
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    yess

  29. anonymous
    • 5 years ago
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    thank you so much!

  30. anonymous
    • 5 years ago
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    good.. u r welcome.

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