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anonymous
 5 years ago
10x^2  11x  6 Factor
anonymous
 5 years ago
10x^2  11x  6 Factor

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0This is in the form of ax^2+bx+c where a=10, b=11, c=6. Find factors of a*c that add up to be b. a*c=(10)(6)=60. What are factors of 60 that add up to be 11

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.015*4=60 and 15+4=11

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0So replace 11x=15x+4x

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we have 10x^215x+4x6

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0What do the first two terms have in common

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this literally by observation. 10= 1*10= 2*5 factor of 6: 1*6=2*3 try mix and match the factors in form (ax+b)(cx+d) where a&c is a pair of factor 10 and b&d a pair of factor 6. and ad+bc=11

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0You can also do trial factors like anfar if you like

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i also have the problem 125n^2 + 50n + 5

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok so 5x(2x3)+2(2x+3)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0(2x+3)(5x+2) which is what anfar got

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0it was suppose to be 5x(2x3)+2(2x3)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0now thats what anfar got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the 2nd problem: first, make the numbers smaller.note that 125,50 and 5 have common factors 5. so now u have: 5(25n^2+10n+1) then, u can try use the mix and match for the equation in the bracket.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would it be 5(5n+ 2)....?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no. it should be 5(5n+1)(5n+1)=5(5n+1)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but then what happens to the 10?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i put it this way: let say u have an equation in form Ax^2+Bx+C: u have to factor it in form of (ax+b)(cx+d) where: a*c=A , b*d=C and ad+bc=B

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the 2nd case, u considering 25n^2+10n+1 so, u hav A=25, B=10 and C=1 note that 1=1*1 or 1*1 since B is positive, u take the positive ones. so, u now have b=d=1 thus, a*c=25 and a+c=10 now, 25=25*1=5*5. 25+1 not equal to 10. so u take a=c=5. therefore u have: 5(5n+1)(5n+1)=5(5n+1)^2 as the answer. u got it?
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