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so we have (6x-9)^(1/3)=3 correct?
to get rid of 1/3 power raise both sides to the 3rd power
no 3cubed 6x-9=3
use that equation thing below this box
is that right?
3 is index instead of 3rd power
oh 3 times that okay
sorry I am new at this
its k solve for the sqrt thing first
divide both sides by 3
to get rid of the sqrt square both sides
I don't get it why do we divide both sides by 3
We are trying to solve for x.
first step to get x by itself is to divide by that 3 since that sqrt is being multiplied by that 3
to undo multiplication by a number you divide by it
so we have 6x-9=1
+9 to both sides giving 6x=10
divide 6 on both sides ( remember to undo multiplication u divide)
Don't forget to check your work
5/3 is my answer
how do I do that
so you said x=5/3. go back to your original problem and where there is a x plug in 5/3
lets see if we get the same thing on both sides and if we do that means it is a solution
3*(6*5/3-9)^(1/2)=3(10-9)^(1/2)=3(1)^(1/2)=3*1=3 since the left side = the right side that means we have x=5/3 is a solution
okay i wrote it down thank you