- anonymous

solve radical 3sq.6x-9=3

- katieb

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- myininaya

so we have (6x-9)^(1/3)=3 correct?

- myininaya

to get rid of 1/3 power raise both sides to the 3rd power

- myininaya

6x-9=3^3

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## More answers

- anonymous

no 3cubed 6x-9=3

- myininaya

?

- myininaya

use that equation thing below this box

- anonymous

3\sqrt{6x-9}=3\]

- myininaya

\[\sqrt{(6x-9)^3}=3\]

- myininaya

is that right?

- anonymous

3 is index instead of 3rd power

- myininaya

\[\sqrt[3]{6x-9}=3\]

- anonymous

\[3\sqrt{6x-9}=3\]

- myininaya

oh 3 times that okay

- anonymous

sorry I am new at this

- myininaya

its k solve for the sqrt thing first

- myininaya

divide both sides by 3

- myininaya

(6x-9)^(1/2)=1

- myininaya

to get rid of the sqrt square both sides

- anonymous

I don't get it why do we divide both sides by 3

- myininaya

We are trying to solve for x.

- anonymous

okay

- myininaya

first step to get x by itself is to divide by that 3 since that sqrt is being multiplied by that 3

- myininaya

to undo multiplication by a number you divide by it

- anonymous

okay

- myininaya

so we have 6x-9=1

- anonymous

okay

- myininaya

+9 to both sides giving 6x=10

- anonymous

okay

- myininaya

divide 6 on both sides ( remember to undo multiplication u divide)

- myininaya

x=10/6=5/3

- myininaya

Don't forget to check your work

- anonymous

5/3 is my answer

- anonymous

how do I do that

- myininaya

so you said x=5/3. go back to your original problem and where there is a x plug in 5/3

- myininaya

lets see if we get the same thing on both sides and if we do that means it is a solution

- myininaya

3*(6*5/3-9)^(1/2)=3(10-9)^(1/2)=3(1)^(1/2)=3*1=3 since the left side = the right side that means we have x=5/3 is a solution

- anonymous

okay i wrote it down thank you

- myininaya

no problem

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