anonymous
  • anonymous
Can you show me how to solve this equation using substitution 5y+4x=8 y=5x+10
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
yes. since it is stated that y = 5x +10; we can just substitute that value for "y" in the other equation and slove for "x"
amistre64
  • amistre64
5(5x + 10) + 4x = 8 25x + 50 + 4x = 8 29x + 50 = 8 29x = 8 - 50 29x = -42 x = -42/29
amistre64
  • amistre64
reduce if you can...

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anonymous
  • anonymous
could you show me what I did wrong ill show you how I solved it
amistre64
  • amistre64
go right ahead :)
anonymous
  • anonymous
5y+4x=8 y=5x+10 5(5x+10)+4x=8 25x+50+4x=8 21x+50=8 21x=-42 x=-2 y=5(-20)+10 y=-10+10 y=0
anonymous
  • anonymous
That is what I did
anonymous
  • anonymous
And I was pretty sure that was the answer.
amistre64
  • amistre64
25x + 4x does NOT equal 21x
anonymous
  • anonymous
Oh sorry I made a typing misatke to y=5(-2)+10 should be the one line
anonymous
  • anonymous
Ithought you subtracted
amistre64
  • amistre64
nope; when it says 25 + 4, it actually means to add. That little (+) sign means add....
anonymous
  • anonymous
I know but I was taught that you did the opposite to get rid of it
amistre64
  • amistre64
why would you want to get rid of it? it is a vital part of the equation. Now, if it was on the OTHER side of the (=) sign, you would subtract it from BOTH sides to move it. But, if it is on the SAME side, it is simply addition.... Does that make sense?
anonymous
  • anonymous
Look at your original question that you asked. Are you sure it doesn't say -4x in the problem you were given? 5y - 4x = 8?
anonymous
  • anonymous
Hold on let me check quick
amistre64
  • amistre64
If you want to move it to the othe side of the (=) sign we do this: 25 + 4 = 29 25 + 4 (-4) = 29 (-4) 25 = 29 - 4 But when it is on the same side, just add it together: 25 + 4 = 29 29 = 29
anonymous
  • anonymous
5y + 4x = 8 y + 5x = 10 it says ''solving a system of equations by substitution''
amistre64
  • amistre64
That is a different set of equations that what you give to begin with; please verify which one is correct please...
anonymous
  • anonymous
Im sorry
anonymous
  • anonymous
The last one is the correct one
amistre64
  • amistre64
ok :) What does "y" equal then?: y = 10 - 5x substitute that "value" into the top equation to get: 5(10 - 5x) + 4x = 8 50 - 25x + 4x = 8 -25x + 4x = 8 -50 -21x = -42 x = -42/-21 = 2 Use this solid value of x=2 in the bottom equation to solve for "y" y + 5(2) = 10 y + 10 = 10 y = 10 - 10 y = 0 x = 2
anonymous
  • anonymous
OK thanks im gonna look over this for a minute
anonymous
  • anonymous
Im sorry im kinda confussed I was taught in a different way and im trying to figure this all out
anonymous
  • anonymous
I got y=5x+10
amistre64
  • amistre64
you gave, for the bottom equation: y + 5x = 10 ; to get "y" all by its little lonesome, we need to subtract (5x) from both sides to keep the same values... y +5x -5x = 10 - 5x y + 0 = 10 - 5x y = 10 - 5x Do you see it?
anonymous
  • anonymous
Not really im sorry
amistre64
  • amistre64
tell me where I am losing you then, let me know what is confusing you here. And then I can show you the right steps...
amistre64
  • amistre64
Can you tell me what the (=) sign means?
anonymous
  • anonymous
See for Y im somehow got -5x+10
amistre64
  • amistre64
-5x + 10 is correct, and it is the same thing as 10-5x am i right or wrong?
anonymous
  • anonymous
Oh so then I did have it right?
amistre64
  • amistre64
you wrote, and I quote " I got y=5x+10" earlier. If what you meant was "I got y= -5x+10" then yes, you are right...
anonymous
  • anonymous
Yeah thats what I meant im sorry I cant type today at all
amistre64
  • amistre64
:) paper and pencil is always easier when doing math
anonymous
  • anonymous
Yeah it is but thanks for showing me that now im gonna rework the problem and see if i get it right
anonymous
  • anonymous
so should the set up be 5(-5x+10)+4x=8
amistre64
  • amistre64
Yes
anonymous
  • anonymous
Ok I think im getting this down now
amistre64
  • amistre64
you are doing great :)
anonymous
  • anonymous
Thanks I have really been having a tough time this year
anonymous
  • anonymous
Does y = 2
anonymous
  • anonymous
and x=0
amistre64
  • amistre64
yes; y=0 and x=2. To double check; plug those values into the original equations to see if they are true.
anonymous
  • anonymous
Ok thanks a lot :)

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