At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
equation of a line can be written in the form (x-x_1)m=y_1-y
we know m=2/5 and we know a point (x_1,y_1)=(-5,-3)
subtract 3 on both sides to put it in the form y=mx+b
i just dont understand how -5 and -3 turned into -1
if we subtract 3 on both sides 2-3=-1
of mx + b?
no you were asking how i got -1 right?
yea i understand the y= 2/5 x just not how u got -1 from (-5, -3)
do you understand where I got 2x/5+2=y+3
not the 2nd 2 and 3
the point slope formula is (x-x_1)m=y-y_1 where in this case a line on this point is (x_1,y_1)=(-5,-3) and m=2/5 since that is the slope of this line
so we have (x-(-5))*2/5=y-(-3)
Use distributive property we have 2x/5+5*2/5=y+3
we want to put this in y=mx+b form which is the slope intercept form
Since the above equation has y by itself we need to solve for y by subtracting 3 on both sides
o okay now i understand thank u
the slope-intercept equation is: y = mx + b You know the slope, and they give you (x=-5,y=-3); so lets plug and play... -3 = (2/5)(-5) +b ; solve for "b". -3 = -2 + b -1 = b throw away your (-5,-3) and use the equation as it: y = (2/5)x - 1