slope intercept form of equation of line through points. through: (-5, -3), slope = 2/5

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slope intercept form of equation of line through points. through: (-5, -3), slope = 2/5

Mathematics
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equation of a line can be written in the form (x-x_1)m=y_1-y
oops (x-x_1)m=y-y_1
we know m=2/5 and we know a point (x_1,y_1)=(-5,-3)

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Other answers:

(x-(-5))2/5=(y-(-3))
(x+5)2/5=y+3
2x/5+5*2/5=y+3
2x/5+2=y+3
subtract 3 on both sides to put it in the form y=mx+b
okay
y=2x/5-1
i just dont understand how -5 and -3 turned into -1
if we subtract 3 on both sides 2-3=-1
of mx + b?
no you were asking how i got -1 right?
yea i understand the y= 2/5 x just not how u got -1 from (-5, -3)
do you understand where I got 2x/5+2=y+3
not the 2nd 2 and 3
the point slope formula is (x-x_1)m=y-y_1 where in this case a line on this point is (x_1,y_1)=(-5,-3) and m=2/5 since that is the slope of this line
so we have (x-(-5))*2/5=y-(-3)
(x+5)*2/5=y+3
Use distributive property we have 2x/5+5*2/5=y+3
we want to put this in y=mx+b form which is the slope intercept form
Since the above equation has y by itself we need to solve for y by subtracting 3 on both sides
2x/5+2-3=y
y=2x/5+2-3
y=2x/5-1
o okay now i understand thank u
cool!
the slope-intercept equation is: y = mx + b You know the slope, and they give you (x=-5,y=-3); so lets plug and play... -3 = (2/5)(-5) +b ; solve for "b". -3 = -2 + b -1 = b throw away your (-5,-3) and use the equation as it: y = (2/5)x - 1

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