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anonymous
 5 years ago
tan^xsec^4x = 1  2sec^2x
anonymous
 5 years ago
tan^xsec^4x = 1  2sec^2x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0...is this supposed to be \[\tan(x)  \sec^4(x) = 12\sec^2(x)\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh no. oops. its tan^4(x)  sec^4(x) = 1  2 sec^2(x)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok you have the difference of squares here a^2+b^2=(ab)(a+b)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so that would make it (tan^2xsec^2x) (tan^2x+sec^2x)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we have (tan^2x)^2(sec^2x)^2=[(tanx)^2+(secx)^2][(tanx)^2(secx)^2]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0yes and 1=(secx)^2(tanx)^2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we have ((tanx)^2+(sec^2))((secx)^2(tanx)^2)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0((tanx)^2+(secx)^2)(1)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok the other side is in terms of sec so put this side in terms of sec

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0this problem is basically done

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we have ((secx)^21+(secx)^2)=(2(secx)^21)=12(secx)^2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0which is the other side of the equation
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