anonymous
  • anonymous
solve sq. y-13 + sq.y =13
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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myininaya
  • myininaya
First get 1 sqrt thingy by itself then square both sides so you can get rid of that sqrt but you will still have another sqrt on the other side so you get that one by itself and then square again
myininaya
  • myininaya
no more sqrt thingy
myininaya
  • myininaya
so we have (y-13)^(1/2)=13-y^1/2

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myininaya
  • myininaya
square both sides
myininaya
  • myininaya
y-13=(13-y^(1/2))^2
anonymous
  • anonymous
sorry to interrupt. @myinaya, like the way you said "sqrt thingy" XD
myininaya
  • myininaya
lol
myininaya
  • myininaya
i just thought it is easier to understand
myininaya
  • myininaya
y-13=169-2y^1/2+y
myininaya
  • myininaya
remember get that last sqrt thingy by itself
myininaya
  • myininaya
y-y-13-169=2y^(1/2)
myininaya
  • myininaya
oh mine thought we ran into some like terms. Lets just combine them real quick
myininaya
  • myininaya
though*
myininaya
  • myininaya
-199=2y^(1/2)
myininaya
  • myininaya
so we have -199/2=y^(1/2) then square both sides (-199/2)^2=y
myininaya
  • myininaya
You should always check your solutions when you raise both sides to an even power though
anonymous
  • anonymous
so y= -199/2^2
anonymous
  • anonymous
y = (-199/2)^2
myininaya
  • myininaya
and actually it was suppose to be (199/2)^2 but it doesnt matter since it is squared
anonymous
  • anonymous
this is so confusing to me ....haven't been in school for 20+ years
myininaya
  • myininaya
like i forgot to write a negative sign before the last step

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