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anonymous

  • 5 years ago

solve sq. y-13 + sq.y =13

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  1. myininaya
    • 5 years ago
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    First get 1 sqrt thingy by itself then square both sides so you can get rid of that sqrt but you will still have another sqrt on the other side so you get that one by itself and then square again

  2. myininaya
    • 5 years ago
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    no more sqrt thingy

  3. myininaya
    • 5 years ago
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    so we have (y-13)^(1/2)=13-y^1/2

  4. myininaya
    • 5 years ago
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    square both sides

  5. myininaya
    • 5 years ago
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    y-13=(13-y^(1/2))^2

  6. anonymous
    • 5 years ago
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    sorry to interrupt. @myinaya, like the way you said "sqrt thingy" XD

  7. myininaya
    • 5 years ago
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    lol

  8. myininaya
    • 5 years ago
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    i just thought it is easier to understand

  9. myininaya
    • 5 years ago
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    y-13=169-2y^1/2+y

  10. myininaya
    • 5 years ago
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    remember get that last sqrt thingy by itself

  11. myininaya
    • 5 years ago
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    y-y-13-169=2y^(1/2)

  12. myininaya
    • 5 years ago
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    oh mine thought we ran into some like terms. Lets just combine them real quick

  13. myininaya
    • 5 years ago
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    though*

  14. myininaya
    • 5 years ago
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    -199=2y^(1/2)

  15. myininaya
    • 5 years ago
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    so we have -199/2=y^(1/2) then square both sides (-199/2)^2=y

  16. myininaya
    • 5 years ago
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    You should always check your solutions when you raise both sides to an even power though

  17. anonymous
    • 5 years ago
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    so y= -199/2^2

  18. anonymous
    • 5 years ago
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    y = (-199/2)^2

  19. myininaya
    • 5 years ago
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    and actually it was suppose to be (199/2)^2 but it doesnt matter since it is squared

  20. anonymous
    • 5 years ago
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    this is so confusing to me ....haven't been in school for 20+ years

  21. myininaya
    • 5 years ago
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    like i forgot to write a negative sign before the last step

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