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anonymous

  • 5 years ago

solve. round to 4th decimals, separate answer with commas if necessary. (x^2)(2x)-(2^x)=0

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  1. anonymous
    • 5 years ago
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    Are you sure you have this entered correctly?

  2. anonymous
    • 5 years ago
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    sorry its \[x ^{2}2^{x}-2^{x}=0\]

  3. anonymous
    • 5 years ago
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    I would factor this.. common factor is 2^x. So you would have 2^x(x^2 - 1) = 0 Then you have the difference of two squares so you have 2^x(x + 1)(x - 1) = 0 So every where there is an "x" there is an answer. So x + 1 would give you an answer of -1 ... x - 1 would give you an answer of 1 When does 2^x = 0?

  4. anonymous
    • 5 years ago
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    x would be 0, so -1 and 1 would work

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