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ln(a) + ln(b) = ln(ab)

That's x^2+x-20?

yep.
now, ln(0) = 1 because e^0 = 1

and also any number to the 0 power except 0 is 1

your equation is really:
x^2 +x - 20 = 0

wait!

or
(x-4) (x+5) = 0

e^1=e

we have (x-4)(x+5)=e

lol..... maybe it does, and maybe it doesnt :)

yes myininaya

if we do it like amistre we would make the problem much easier but also kindof wrong

and kindof wrong is just wrong

now im confused >_<

horseshoe and handgranades me friend :)

so we have x^2-9x+20+e=0

oops -e

wouldnt it be -e?

Yes i blame amistre

lol

bring over 1 to the left at the start...before changinglg form...

...its my liver pills...blame the liver pills :)

so whats the answer?

sorry...doesn't make a difference what I said

Quadratic formula the way to go

this is what i put on the formula
-1+squareroot(1^2 -4(1)(20-e))))/2

no

a=1 n=-9 c=20-e correct?

c=-20-e

b=-9*

b=1

no b =1

dont listen to me

im doing two things at once sorry

my calculator wont work

correct!

that negative number gives you another negative number when you plug it into x-4