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donovan11
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Solve the logarithmic equation for . Please round the answer to four decimal places, if necessary.
ln(x4)+ln(x+5)=1
 3 years ago
 3 years ago
donovan11 Group Title
Solve the logarithmic equation for . Please round the answer to four decimal places, if necessary. ln(x4)+ln(x+5)=1
 3 years ago
 3 years ago

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donovan11 Group TitleBest ResponseYou've already chosen the best response.0
Reason I'm confused is because unlike log, in ln the exponential form is e^y=x and I'm having trouble solving the rest
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
ln(a) + ln(b) = ln(ab)
 3 years ago

donovan11 Group TitleBest ResponseYou've already chosen the best response.0
That's x^2+x20?
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
yep. now, ln(0) = 1 because e^0 = 1
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
and also any number to the 0 power except 0 is 1
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
your equation is really: x^2 +x  20 = 0
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
or (x4) (x+5) = 0
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
we have (x4)(x+5)=e
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
lol..... maybe it does, and maybe it doesnt :)
 3 years ago

beens Group TitleBest ResponseYou've already chosen the best response.0
yes myininaya
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
if we do it like amistre we would make the problem much easier but also kindof wrong
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
and kindof wrong is just wrong
 3 years ago

donovan11 Group TitleBest ResponseYou've already chosen the best response.0
now im confused >_<
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
horseshoe and handgranades me friend :)
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
so we have x^29x+20+e=0
 3 years ago

donovan11 Group TitleBest ResponseYou've already chosen the best response.0
wouldnt it be e?
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
Yes i blame amistre
 3 years ago

beens Group TitleBest ResponseYou've already chosen the best response.0
bring over 1 to the left at the start...before changinglg form...
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
...its my liver pills...blame the liver pills :)
 3 years ago

donovan11 Group TitleBest ResponseYou've already chosen the best response.0
so whats the answer?
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
use quadractic formula x=(9@sqrt(814(1)(20e))/2 where @ means + or , but make sure your answer is positive because you cannot do ln(negative)
 3 years ago

beens Group TitleBest ResponseYou've already chosen the best response.0
sorry...doesn't make a difference what I said
 3 years ago

beens Group TitleBest ResponseYou've already chosen the best response.0
Quadratic formula the way to go
 3 years ago

donovan11 Group TitleBest ResponseYou've already chosen the best response.0
this is what i put on the formula 1+squareroot(1^2 4(1)(20e))))/2
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
a=1 n=9 c=20e correct?
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
dont listen to me
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
im doing two things at once sorry
 3 years ago

donovan11 Group TitleBest ResponseYou've already chosen the best response.0
my calculator wont work
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
(1+sqrt(14(20e))/2=4.2925 and (1sqrt(14(20e))/2=5.2925 but we can't use 5.2925 since it is negative and the natural log of a negative number doesnt exist
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
x can be negative if it is not the only thing controling the value of the log. the thing is: x4 needs to be greater than 0 and, x+5 needs to be greater than 0. x >4 serves both cases.
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
that negative number gives you another negative number when you plug it into x4
 3 years ago
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