anonymous
  • anonymous
Solve the logarithmic equation for . Please round the answer to four decimal places, if necessary. ln(x-4)+ln(x+5)=1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Reason I'm confused is because unlike log, in ln the exponential form is e^y=x and I'm having trouble solving the rest
amistre64
  • amistre64
ln(a) + ln(b) = ln(ab)
anonymous
  • anonymous
That's x^2+x-20?

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More answers

amistre64
  • amistre64
yep. now, ln(0) = 1 because e^0 = 1
myininaya
  • myininaya
and also any number to the 0 power except 0 is 1
amistre64
  • amistre64
your equation is really: x^2 +x - 20 = 0
myininaya
  • myininaya
wait!
amistre64
  • amistre64
or (x-4) (x+5) = 0
myininaya
  • myininaya
e^1=e
myininaya
  • myininaya
we have (x-4)(x+5)=e
amistre64
  • amistre64
lol..... maybe it does, and maybe it doesnt :)
anonymous
  • anonymous
yes myininaya
myininaya
  • myininaya
if we do it like amistre we would make the problem much easier but also kindof wrong
myininaya
  • myininaya
and kindof wrong is just wrong
anonymous
  • anonymous
now im confused >_<
amistre64
  • amistre64
horseshoe and handgranades me friend :)
myininaya
  • myininaya
so we have x^2-9x+20+e=0
myininaya
  • myininaya
oops -e
anonymous
  • anonymous
wouldnt it be -e?
myininaya
  • myininaya
Yes i blame amistre
myininaya
  • myininaya
lol
anonymous
  • anonymous
bring over 1 to the left at the start...before changinglg form...
amistre64
  • amistre64
...its my liver pills...blame the liver pills :)
anonymous
  • anonymous
so whats the answer?
myininaya
  • myininaya
use quadractic formula x=(9@sqrt(81-4(1)(20-e))/2 where @ means + or -, but make sure your answer is positive because you cannot do ln(negative)
anonymous
  • anonymous
sorry...doesn't make a difference what I said
anonymous
  • anonymous
Quadratic formula the way to go
anonymous
  • anonymous
this is what i put on the formula -1+squareroot(1^2 -4(1)(20-e))))/2
myininaya
  • myininaya
no
myininaya
  • myininaya
a=1 n=-9 c=20-e correct?
anonymous
  • anonymous
c=-20-e
myininaya
  • myininaya
b=-9*
anonymous
  • anonymous
b=1
anonymous
  • anonymous
no b =1
myininaya
  • myininaya
dont listen to me
myininaya
  • myininaya
im doing two things at once sorry
anonymous
  • anonymous
my calculator wont work
myininaya
  • myininaya
(-1+sqrt(1-4(-20-e))/2=4.2925 and (-1-sqrt(1-4(-20-e))/2=-5.2925 but we can't use -5.2925 since it is negative and the natural log of a negative number doesnt exist
amistre64
  • amistre64
x can be negative if it is not the only thing controling the value of the log. the thing is: x-4 needs to be greater than 0 and, x+5 needs to be greater than 0. x >4 serves both cases.
myininaya
  • myininaya
correct!
myininaya
  • myininaya
that negative number gives you another negative number when you plug it into x-4

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