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anonymous
 5 years ago
csc t/sec^2t*sin tsin t cost^2t/cos^2t
anonymous
 5 years ago
csc t/sec^2t*sin tsin t cost^2t/cos^2t

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh sorry. yes simplifying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Put everything in terms of sin(t) and cos(t)...I can't quite identify if you're multiplying the denominator of the first term by sin(t) or the whole fraction. Could you please clarify with the equation editor as a response?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0yes i agree with modulus. i cant read.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0okay cool so cscx=1/sinx and 1/(secx)^2=(cosx)^2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0We have now that [(cost)^2/sint]*[(sintsint(cost)^2/(cost)^2]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0we see that (cost)^2 cancel giving us (sintsint(cost)^2)/sint

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0But oh mine there is a sint in each term so we can cancel a sint from each term because sint/sint=1: (1(cost)^2)/1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0But (sint)^2+(cost)^2=1 so 1(cost)^2=(sint)^2
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