anonymous
  • anonymous
csc t/sec^2t*sin t-sin t cost^2t/cos^2t
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
myininaya
  • myininaya
what are we doing?
myininaya
  • myininaya
simplifying?
anonymous
  • anonymous
oh sorry. yes simplifying

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Put everything in terms of sin(t) and cos(t)...I can't quite identify if you're multiplying the denominator of the first term by sin(t) or the whole fraction. Could you please clarify with the equation editor as a response?
myininaya
  • myininaya
yes i agree with modulus. i cant read.
anonymous
  • anonymous
1 Attachment
myininaya
  • myininaya
okay cool so cscx=1/sinx and 1/(secx)^2=(cosx)^2
myininaya
  • myininaya
We have now that [(cost)^2/sint]*[(sint-sint(cost)^2/(cost)^2]
myininaya
  • myininaya
we see that (cost)^2 cancel giving us (sint-sint(cost)^2)/sint
myininaya
  • myininaya
But oh mine there is a sint in each term so we can cancel a sint from each term because sint/sint=1: (1-(cost)^2)/1
myininaya
  • myininaya
But (sint)^2+(cost)^2=1 so 1-(cost)^2=(sint)^2
anonymous
  • anonymous
thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.