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anonymous

  • 5 years ago

csc t/sec^2t*sin t-sin t cost^2t/cos^2t

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  1. myininaya
    • 5 years ago
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    what are we doing?

  2. myininaya
    • 5 years ago
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    simplifying?

  3. anonymous
    • 5 years ago
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    oh sorry. yes simplifying

  4. anonymous
    • 5 years ago
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    Put everything in terms of sin(t) and cos(t)...I can't quite identify if you're multiplying the denominator of the first term by sin(t) or the whole fraction. Could you please clarify with the equation editor as a response?

  5. myininaya
    • 5 years ago
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    yes i agree with modulus. i cant read.

  6. anonymous
    • 5 years ago
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  7. myininaya
    • 5 years ago
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    okay cool so cscx=1/sinx and 1/(secx)^2=(cosx)^2

  8. myininaya
    • 5 years ago
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    We have now that [(cost)^2/sint]*[(sint-sint(cost)^2/(cost)^2]

  9. myininaya
    • 5 years ago
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    we see that (cost)^2 cancel giving us (sint-sint(cost)^2)/sint

  10. myininaya
    • 5 years ago
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    But oh mine there is a sint in each term so we can cancel a sint from each term because sint/sint=1: (1-(cost)^2)/1

  11. myininaya
    • 5 years ago
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    But (sint)^2+(cost)^2=1 so 1-(cost)^2=(sint)^2

  12. anonymous
    • 5 years ago
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    thanks

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