csc t/sec^2t*sin t-sin t cost^2t/cos^2t

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

csc t/sec^2t*sin t-sin t cost^2t/cos^2t

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

what are we doing?
simplifying?
oh sorry. yes simplifying

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Put everything in terms of sin(t) and cos(t)...I can't quite identify if you're multiplying the denominator of the first term by sin(t) or the whole fraction. Could you please clarify with the equation editor as a response?
yes i agree with modulus. i cant read.
1 Attachment
okay cool so cscx=1/sinx and 1/(secx)^2=(cosx)^2
We have now that [(cost)^2/sint]*[(sint-sint(cost)^2/(cost)^2]
we see that (cost)^2 cancel giving us (sint-sint(cost)^2)/sint
But oh mine there is a sint in each term so we can cancel a sint from each term because sint/sint=1: (1-(cost)^2)/1
But (sint)^2+(cost)^2=1 so 1-(cost)^2=(sint)^2
thanks

Not the answer you are looking for?

Search for more explanations.

Ask your own question