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  1. beens
    • 3 years ago
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    not getting through with the link

  2. generallyclay
    • 3 years ago
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    the link works you just need to copy and paste the whole link, not just what is underlined

  3. DavisAshley
    • 3 years ago
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    can someone help me with 8-12?

  4. generallyclay
    • 3 years ago
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    could you be more specific with what you are finding difficult about, for instance # 8?

  5. DavisAshley
    • 3 years ago
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    i just dont know how to do them

  6. DavisAshley
    • 3 years ago
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    like if i can just get the equation i can find the answers.. i just need the equation

  7. generallyclay
    • 3 years ago
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    well in # 8 the tringle is an equilateral triangle, so you know all the angles already. Since you are given the radius of the circle, you can use the equation A=pi*r^2

  8. generallyclay
    • 3 years ago
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    to find the area of the circle and then subtract the area of the triangle from the area of the circle.

  9. generallyclay
    • 3 years ago
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    the sides of the triangle are all 6 btw

  10. DavisAshley
    • 3 years ago
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    so the area of the triangle is 15.59

  11. DavisAshley
    • 3 years ago
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    so the circle area would be about 34.65?

  12. generallyclay
    • 3 years ago
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    one sec

  13. generallyclay
    • 3 years ago
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    first cut the triangle in half to make two right angle triangles. then you can use pythagorean to find the height of the triangle, which i got to be sqrt(27). finding the area of the triangle with half base times height formula, 1/2*6*sqrt(27) = 9sqrt(3) =15.59. Is that what you did?

  14. DavisAshley
    • 3 years ago
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    yea

  15. generallyclay
    • 3 years ago
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    for the area of the circle did you use pi*r^2?

  16. DavisAshley
    • 3 years ago
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    yeah and i got 50.24

  17. generallyclay
    • 3 years ago
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    plugging in 16 for r^2, i got the area to be 50.27

  18. generallyclay
    • 3 years ago
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    so subtract the area of the triangle from the area of the circle to find the area of the shaded region

  19. DavisAshley
    • 3 years ago
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    34.68

  20. generallyclay
    • 3 years ago
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    super

  21. DavisAshley
    • 3 years ago
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    would it be squared?

  22. generallyclay
    • 3 years ago
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    no, why would you?

  23. DavisAshley
    • 3 years ago
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    idk.. someone helped me with number 7 and they squared it

  24. generallyclay
    • 3 years ago
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    might have been part of finding the area of a circle, you need to square the radius for that

  25. generallyclay
    • 3 years ago
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    we already did that, though, so it's fine as it is

  26. DavisAshley
    • 3 years ago
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    okay.. will you help me with the other ones

  27. generallyclay
    • 3 years ago
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    well, I have a bit of hw of my own that i must do before tomorrow, but take a look at number 12... I want to try doing that one with you.

  28. generallyclay
    • 3 years ago
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    if you like

  29. DavisAshley
    • 3 years ago
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    ok

  30. generallyclay
    • 3 years ago
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    This is a really cool and beautiful one out of the lot. do you see any way of starting to think about it?

  31. DavisAshley
    • 3 years ago
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    doing A=pi*r^2

  32. generallyclay
    • 3 years ago
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    that would give you the area of the circle, it's true. but look even more closely: there are only two lines in the triangle that you do not know the length of... right?

  33. DavisAshley
    • 3 years ago
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    yea

  34. generallyclay
    • 3 years ago
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    oops... I meant to say in the circle

  35. generallyclay
    • 3 years ago
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    and do you know the equation to find a sector a circle?

  36. DavisAshley
    • 3 years ago
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    arc divided by 360* pi*r^2

  37. generallyclay
    • 3 years ago
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    A=1/2*r^2*theta

  38. generallyclay
    • 3 years ago
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    actually since each of these sectors is 1/4 of the circle, the equation is A=1/4*pi*r^2

  39. generallyclay
    • 3 years ago
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    do you see where I'm going with this?

  40. DavisAshley
    • 3 years ago
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    so a=1/4*3.14*6^2

  41. DavisAshley
    • 3 years ago
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    =28.26

  42. generallyclay
    • 3 years ago
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    well the area of the triangle is 18 right?

  43. DavisAshley
    • 3 years ago
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    yea

  44. generallyclay
    • 3 years ago
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    good, and so given that you now have the area of a quarter of a circle, and the area of the triangle, you can subtract the area of the triangle away from the area of the quarter of the circle that you have.

  45. generallyclay
    • 3 years ago
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    sorry i skipped a step before. have you followed me up to this point or are you a bit lost?

  46. generallyclay
    • 3 years ago
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    So, here are the steps. 1) we found the area of a quarter of a circle. 2) we found the area of the triangle. 3) we subtract the area of the triangle from the area of the quarter of the circle in order to find the area of one of the shaded regions.

  47. generallyclay
    • 3 years ago
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    but since both of the triangles are the same, we also now know the area of the other shaded region. does that make sense?

  48. DavisAshley
    • 3 years ago
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    yea

  49. generallyclay
    • 3 years ago
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    Awesome. I'm glad I could help :) This is my first time on this site, but this is a pretty cool idea for a site.

  50. DavisAshley
    • 3 years ago
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    yeah

  51. generallyclay
    • 3 years ago
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    well I have to go do HW now, good luck!

  52. DavisAshley
    • 3 years ago
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    thank you for your help

  53. generallyclay
    • 3 years ago
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    no problem

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