anonymous
  • anonymous
will someone please go to this website i need help with problems 8-12 please http://docs.google.com/viewer?a=v&q=cache:s_Z6mEDtqnAJ:www.somersclassroom.com/files/Chapter%252011/11.5B.pdf+Answers+to+Practice+B+11.5+Geometry&hl=en&gl=us&pid=bl&srcid=ADGEEShpElU6i2Z7y85NrrTvbtv6Xn4WJVYyv7dLeO0itxvLzove7oq8uuVBixJhT8WeHarT3fU7H8VLiD-lB3r80ml3tteJXW5mtG0dWFZFEwSrLDZiHxlXHME_wCAUoHME2QVUFMpY&sig=AHIEtbRN3mHn7LH_nAJkKRNhqf_6RQ8gLw
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
not getting through with the link
anonymous
  • anonymous
the link works you just need to copy and paste the whole link, not just what is underlined
anonymous
  • anonymous
can someone help me with 8-12?

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anonymous
  • anonymous
could you be more specific with what you are finding difficult about, for instance # 8?
anonymous
  • anonymous
i just dont know how to do them
anonymous
  • anonymous
like if i can just get the equation i can find the answers.. i just need the equation
anonymous
  • anonymous
well in # 8 the tringle is an equilateral triangle, so you know all the angles already. Since you are given the radius of the circle, you can use the equation A=pi*r^2
anonymous
  • anonymous
to find the area of the circle and then subtract the area of the triangle from the area of the circle.
anonymous
  • anonymous
the sides of the triangle are all 6 btw
anonymous
  • anonymous
so the area of the triangle is 15.59
anonymous
  • anonymous
so the circle area would be about 34.65?
anonymous
  • anonymous
one sec
anonymous
  • anonymous
first cut the triangle in half to make two right angle triangles. then you can use pythagorean to find the height of the triangle, which i got to be sqrt(27). finding the area of the triangle with half base times height formula, 1/2*6*sqrt(27) = 9sqrt(3) =15.59. Is that what you did?
anonymous
  • anonymous
yea
anonymous
  • anonymous
for the area of the circle did you use pi*r^2?
anonymous
  • anonymous
yeah and i got 50.24
anonymous
  • anonymous
plugging in 16 for r^2, i got the area to be 50.27
anonymous
  • anonymous
so subtract the area of the triangle from the area of the circle to find the area of the shaded region
anonymous
  • anonymous
34.68
anonymous
  • anonymous
super
anonymous
  • anonymous
would it be squared?
anonymous
  • anonymous
no, why would you?
anonymous
  • anonymous
idk.. someone helped me with number 7 and they squared it
anonymous
  • anonymous
might have been part of finding the area of a circle, you need to square the radius for that
anonymous
  • anonymous
we already did that, though, so it's fine as it is
anonymous
  • anonymous
okay.. will you help me with the other ones
anonymous
  • anonymous
well, I have a bit of hw of my own that i must do before tomorrow, but take a look at number 12... I want to try doing that one with you.
anonymous
  • anonymous
if you like
anonymous
  • anonymous
ok
anonymous
  • anonymous
This is a really cool and beautiful one out of the lot. do you see any way of starting to think about it?
anonymous
  • anonymous
doing A=pi*r^2
anonymous
  • anonymous
that would give you the area of the circle, it's true. but look even more closely: there are only two lines in the triangle that you do not know the length of... right?
anonymous
  • anonymous
yea
anonymous
  • anonymous
oops... I meant to say in the circle
anonymous
  • anonymous
and do you know the equation to find a sector a circle?
anonymous
  • anonymous
arc divided by 360* pi*r^2
anonymous
  • anonymous
A=1/2*r^2*theta
anonymous
  • anonymous
actually since each of these sectors is 1/4 of the circle, the equation is A=1/4*pi*r^2
anonymous
  • anonymous
do you see where I'm going with this?
anonymous
  • anonymous
so a=1/4*3.14*6^2
anonymous
  • anonymous
=28.26
anonymous
  • anonymous
well the area of the triangle is 18 right?
anonymous
  • anonymous
yea
anonymous
  • anonymous
good, and so given that you now have the area of a quarter of a circle, and the area of the triangle, you can subtract the area of the triangle away from the area of the quarter of the circle that you have.
anonymous
  • anonymous
sorry i skipped a step before. have you followed me up to this point or are you a bit lost?
anonymous
  • anonymous
So, here are the steps. 1) we found the area of a quarter of a circle. 2) we found the area of the triangle. 3) we subtract the area of the triangle from the area of the quarter of the circle in order to find the area of one of the shaded regions.
anonymous
  • anonymous
but since both of the triangles are the same, we also now know the area of the other shaded region. does that make sense?
anonymous
  • anonymous
yea
anonymous
  • anonymous
Awesome. I'm glad I could help :) This is my first time on this site, but this is a pretty cool idea for a site.
anonymous
  • anonymous
yeah
anonymous
  • anonymous
well I have to go do HW now, good luck!
anonymous
  • anonymous
thank you for your help
anonymous
  • anonymous
no problem

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