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anonymous
 5 years ago
will someone please go to this website i need help with problems 812 please
http://docs.google.com/viewer?a=v&q=cache:s_Z6mEDtqnAJ:www.somersclassroom.com/files/Chapter%252011/11.5B.pdf+Answers+to+Practice+B+11.5+Geometry&hl=en&gl=us&pid=bl&srcid=ADGEEShpElU6i2Z7y85NrrTvbtv6Xn4WJVYyv7dLeO0itxvLzove7oq8uuVBixJhT8WeHarT3fU7H8VLiDlB3r80ml3tteJXW5mtG0dWFZFEwSrLDZiHxlXHME_wCAUoHME2QVUFMpY&sig=AHIEtbRN3mHn7LH_nAJkKRNhqf_6RQ8gLw
anonymous
 5 years ago
will someone please go to this website i need help with problems 812 please http://docs.google.com/viewer?a=v&q=cache:s_Z6mEDtqnAJ:www.somersclassroom.com/files/Chapter%252011/11.5B.pdf+Answers+to+Practice+B+11.5+Geometry&hl=en&gl=us&pid=bl&srcid=ADGEEShpElU6i2Z7y85NrrTvbtv6Xn4WJVYyv7dLeO0itxvLzove7oq8uuVBixJhT8WeHarT3fU7H8VLiDlB3r80ml3tteJXW5mtG0dWFZFEwSrLDZiHxlXHME_wCAUoHME2QVUFMpY&sig=AHIEtbRN3mHn7LH_nAJkKRNhqf_6RQ8gLw

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not getting through with the link

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the link works you just need to copy and paste the whole link, not just what is underlined

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can someone help me with 812?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could you be more specific with what you are finding difficult about, for instance # 8?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just dont know how to do them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0like if i can just get the equation i can find the answers.. i just need the equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well in # 8 the tringle is an equilateral triangle, so you know all the angles already. Since you are given the radius of the circle, you can use the equation A=pi*r^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to find the area of the circle and then subtract the area of the triangle from the area of the circle.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the sides of the triangle are all 6 btw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the area of the triangle is 15.59

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the circle area would be about 34.65?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first cut the triangle in half to make two right angle triangles. then you can use pythagorean to find the height of the triangle, which i got to be sqrt(27). finding the area of the triangle with half base times height formula, 1/2*6*sqrt(27) = 9sqrt(3) =15.59. Is that what you did?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the area of the circle did you use pi*r^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0plugging in 16 for r^2, i got the area to be 50.27

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so subtract the area of the triangle from the area of the circle to find the area of the shaded region

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk.. someone helped me with number 7 and they squared it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0might have been part of finding the area of a circle, you need to square the radius for that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we already did that, though, so it's fine as it is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay.. will you help me with the other ones

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well, I have a bit of hw of my own that i must do before tomorrow, but take a look at number 12... I want to try doing that one with you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is a really cool and beautiful one out of the lot. do you see any way of starting to think about it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that would give you the area of the circle, it's true. but look even more closely: there are only two lines in the triangle that you do not know the length of... right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops... I meant to say in the circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and do you know the equation to find a sector a circle?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0arc divided by 360* pi*r^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually since each of these sectors is 1/4 of the circle, the equation is A=1/4*pi*r^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you see where I'm going with this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well the area of the triangle is 18 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good, and so given that you now have the area of a quarter of a circle, and the area of the triangle, you can subtract the area of the triangle away from the area of the quarter of the circle that you have.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i skipped a step before. have you followed me up to this point or are you a bit lost?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, here are the steps. 1) we found the area of a quarter of a circle. 2) we found the area of the triangle. 3) we subtract the area of the triangle from the area of the quarter of the circle in order to find the area of one of the shaded regions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but since both of the triangles are the same, we also now know the area of the other shaded region. does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Awesome. I'm glad I could help :) This is my first time on this site, but this is a pretty cool idea for a site.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well I have to go do HW now, good luck!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you for your help
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