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anonymous

  • 5 years ago

If E and F are independent events, find P(F) if P(E) = 0.5 and P ( E u F) = 0.8. Round your answer to 3 decimal places. P(F) =

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  1. anonymous
    • 5 years ago
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    \[P(E \cup F)=P(E)+P(F) - P(E and F)\]Here P(E and F) is zero since the events are independent. So you have\[P(E \cup F)=P(E)+P(F) \rightarrow P(F)=P(E \cup F)-P(E)=0.8-0.5=0.3\]

  2. anonymous
    • 5 years ago
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    To three decimal places, 0.300

  3. anonymous
    • 5 years ago
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    You have to remember the first formula to get anywhere.

  4. anonymous
    • 5 years ago
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    when i put that in as an answer it says it is wrong

  5. anonymous
    • 5 years ago
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    Hmm, I'm pretty sure that's the answer. Is this an online test or something?

  6. anonymous
    • 5 years ago
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    no my probability class works off of a thing called wiley plus it gives you questions and i have four tries to get it

  7. anonymous
    • 5 years ago
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    Hang on...

  8. anonymous
    • 5 years ago
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    kk

  9. anonymous
    • 5 years ago
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    Sorry...only had a few hours sleep and distracted...what we should have done is realized:\[P(E and F)=P(E)P(F)\]which isn't zero.

  10. anonymous
    • 5 years ago
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    No problem lol as long as you can help me some

  11. anonymous
    • 5 years ago
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    Technically,\[P(A|B)=\frac{P(A and B)}{P(B)} \rightarrow = P(A|B)P(B)=P(A and B)\]

  12. anonymous
    • 5 years ago
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    Now, P(A|B) = P(A) since it's independent of B, so P(E and F) = P(E)P(F) here.

  13. anonymous
    • 5 years ago
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    Then\[P(E \cup F) = P(E)+P(F)+P(E)P(F)=P(E)+P(F)(1+P(E))\]

  14. anonymous
    • 5 years ago
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    \[\frac{P(E \cup F)-P(E)}{1+P(E)}=P(F)\]

  15. anonymous
    • 5 years ago
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    Are these formulas coming through?

  16. anonymous
    • 5 years ago
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    somewhat I am trying to see the numbers going with it but im just confusing myself

  17. anonymous
    • 5 years ago
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    P(F)=[P(E or F)-P(E)]/[1-P(E)]

  18. anonymous
    • 5 years ago
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    so P(F)=[0.8 - 0.5]/[1-0.5] = 0.3/0.5 = 0.600

  19. anonymous
    • 5 years ago
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    How many goes on your Wiley thing do you have left?

  20. anonymous
    • 5 years ago
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    I had one more and that answer was correct so now i have to just figure out i think more problems and i will be good thanks so much for your help

  21. anonymous
    • 5 years ago
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    good! i'm relieved...

  22. anonymous
    • 5 years ago
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    because I made another mistake typing out, though on my notepad it's right...good luck

  23. anonymous
    • 5 years ago
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    fan me if you like :) need the points.

  24. anonymous
    • 5 years ago
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    okay no problem take a look at some of the other problems i have up if you have the time

  25. anonymous
    • 5 years ago
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    If I can, I will :)

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