anonymous
  • anonymous
If E and F are independent events, find P(F) if P(E) = 0.5 and P ( E u F) = 0.8. Round your answer to 3 decimal places. P(F) =
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[P(E \cup F)=P(E)+P(F) - P(E and F)\]Here P(E and F) is zero since the events are independent. So you have\[P(E \cup F)=P(E)+P(F) \rightarrow P(F)=P(E \cup F)-P(E)=0.8-0.5=0.3\]
anonymous
  • anonymous
To three decimal places, 0.300
anonymous
  • anonymous
You have to remember the first formula to get anywhere.

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anonymous
  • anonymous
when i put that in as an answer it says it is wrong
anonymous
  • anonymous
Hmm, I'm pretty sure that's the answer. Is this an online test or something?
anonymous
  • anonymous
no my probability class works off of a thing called wiley plus it gives you questions and i have four tries to get it
anonymous
  • anonymous
Hang on...
anonymous
  • anonymous
kk
anonymous
  • anonymous
Sorry...only had a few hours sleep and distracted...what we should have done is realized:\[P(E and F)=P(E)P(F)\]which isn't zero.
anonymous
  • anonymous
No problem lol as long as you can help me some
anonymous
  • anonymous
Technically,\[P(A|B)=\frac{P(A and B)}{P(B)} \rightarrow = P(A|B)P(B)=P(A and B)\]
anonymous
  • anonymous
Now, P(A|B) = P(A) since it's independent of B, so P(E and F) = P(E)P(F) here.
anonymous
  • anonymous
Then\[P(E \cup F) = P(E)+P(F)+P(E)P(F)=P(E)+P(F)(1+P(E))\]
anonymous
  • anonymous
\[\frac{P(E \cup F)-P(E)}{1+P(E)}=P(F)\]
anonymous
  • anonymous
Are these formulas coming through?
anonymous
  • anonymous
somewhat I am trying to see the numbers going with it but im just confusing myself
anonymous
  • anonymous
P(F)=[P(E or F)-P(E)]/[1-P(E)]
anonymous
  • anonymous
so P(F)=[0.8 - 0.5]/[1-0.5] = 0.3/0.5 = 0.600
anonymous
  • anonymous
How many goes on your Wiley thing do you have left?
anonymous
  • anonymous
I had one more and that answer was correct so now i have to just figure out i think more problems and i will be good thanks so much for your help
anonymous
  • anonymous
good! i'm relieved...
anonymous
  • anonymous
because I made another mistake typing out, though on my notepad it's right...good luck
anonymous
  • anonymous
fan me if you like :) need the points.
anonymous
  • anonymous
okay no problem take a look at some of the other problems i have up if you have the time
anonymous
  • anonymous
If I can, I will :)

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