anonymous
  • anonymous
three jars contain colored balls as follows: Jar Red White Blue I 10 1 9 II 2 5 13 III 9 1 10 One jar is chosen at random and a ball is withdrawn. The ball is red. What is the probability that it came from jar I? Round to four decimals
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
So there's a \(\frac{1}{3}\) chance that the jar you chose was jar one, and a \(\frac{10}{20}\) chance that you chose a red ball if you the first jar. Now you need to combine these two numbers to get the overall probability you're looking for. Do you know how to combine them?
anonymous
  • anonymous
you do you mean like multiple 1/3 by 10/20
anonymous
  • anonymous
Exactly. Does that make sense?

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anonymous
  • anonymous
i got an answer of .1667 but when i put it as my answer it says its wrong
anonymous
  • anonymous
Hm. Odd. Let me think on it.
anonymous
  • anonymous
There's a chance that what it's looking for is--given the fact that you already chose a red ball, what are the chances it was in the first jar. In that case, you realize that there are \(21\) ways to get a red ball. \(10\) of those ways are in the first jar, so you can get the probability from there.
anonymous
  • anonymous
so i would multiple 10 times 21
anonymous
  • anonymous
So the probability would be... out of the \(21\) overall chances, how many occur in the first jar. That would be dividing the two.
anonymous
  • anonymous
okay now I got it thanks alot

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