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LaddiusMaximus

  • 5 years ago

tanx(1-sin^2x)=1/2sin2x

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  1. anonymous
    • 5 years ago
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    \[1-\sin^2(x)=\cos^2(x)\] Plug in, multiply by sin(x)/cos(x) (ends up being sin(x)cos(x)) and simplify.

  2. LaddiusMaximus
    • 5 years ago
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    I got that part. and tanx becomes sinx/cosx, which leaves me with sinx/cosx(cos^2x) whats after that? algebra?

  3. LaddiusMaximus
    • 5 years ago
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    i end up with sinx/cosx but how does that equal 1/2sin2x?

  4. anonymous
    • 5 years ago
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    Is it (1/2)sin2x or 1/(2sin(2x)?

  5. LaddiusMaximus
    • 5 years ago
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    (1/2)sin2x

  6. anonymous
    • 5 years ago
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    Okay, sin(x)/sin(2x) simplifies to 1/(2cos(x)).\[\sin(x)\cos(x) = (1/2)\sin(2x) \rightarrow\] Seems like if we go down this road, we're just going to end up with 1/2 = 1/2...

  7. LaddiusMaximus
    • 5 years ago
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    whatt identity would that be?

  8. anonymous
    • 5 years ago
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    sin(2x) = 2sin(x)cos(x)

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