What is 2^5x+3=1/8 in exponential form for logarithmic equations?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

What is 2^5x+3=1/8 in exponential form for logarithmic equations?

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I'm not sure what you mean, but I think you want the equation in logarithmic form? Because it's already in exponential form.
Sorry.. I mean to say solve this equation using algebraic procedure. Its a logarithmic equation. So here is the equation once again: 2^5x+3=1/8
If that's the case, then do the following: 1) subtract 3 to the other side 2^(5x)=(1/8)-3 2) Take the log base 2 of both sides following the rule y = log2(x), 2^y=x \[\log_{2} (2^{5x})=\log_{2}(1/8 - 3)\] 3) The log base 2 cancels the 2 in 2^5x leaving you with 5x \[5x=\log_{2}(1/8-3)\] 4) divide both sides by 5 \[x=\log_2(1/8-3)/5\] This is a logarithmic equation because it has logarithms in it. This is different from an exponential equation which you provided. In fact, it is the inverse.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

But the answer in my textbook is -6/5.. LOL!
I think I wrote the problem wrong.. its 2^(5x+3)=1/8
Okay, so the steps are the same. 1) Take the log base 2 of both sides because your base in the exponential function 2^(5x+3) is 2. \[\log_{2}(2^{5x+3})=\log_2(1/8) \] 2) Using the logarithm property \[\log_a(a^{x}) = x\] where x is some function, employ the property on the left hand side of the equation to get\[5x+3=\log_{2}(1/8) \] 3) Another logarithm property states that\[\log_{a}(x/y)=\log_a(x)-\log_a(y) \]where x and y are some function, employ this on the right hand side to get\[5x+3=\log_2(1)-\log_2(8)\] 4) loga(x) = N is equivalent to a^N=x so 2^N=1 when N=0 and 2^N=8 when N=3 giving you\[5x+3=0-3=-3\] 5) Subtract 3 on both sides of the equation and divide both sides of the equation by 5 to get\[x=(-3-3)/5 = -6/5\]
Thank you so much for your help. :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question