Please help.. I need to find the area of the shaded regions
Stacey Warren - Expert brainly.com
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Fr the first image notice that half of the annulus is shaded so
½(36π-π16) = Sum of area of shaded parts
For #10. (49π-π) = area of non shaded part
I take that back.
ans for #10 is wrong
Here's a helpful diagram:
OP = 6
since OPB is a special triangle, PB = 6√3
OB = OC = OA = 2*6=12 (because they are all equidistant)
Area of triangle = ½*base*height
base = 2*PB
height = OP+OC
base = 2*6√3 = 12√3
height = 6+12 = 18
Therefore area of shaded part = 108√3 - 36π
That was #11
so #11 is 865.92
There are a couple of ways to do #12
area of quadrant with shaded part = 1/4*area of circle
=1/4*π*36 = 9π
Area of triangle within quadrant = ½(6*6) = 18
Area of shaded part in first quadrant = 9π-18
We have to shaded parts in the circle so total are of shaded part
= 2(9π-18) = 18π-36 or 18(π-2)
area of half circle = 1/2*π*36 = 18π
area of triangle = 1/2*12*6 = 36
Area of shaded parts = 18π-36 or 18(π-2)