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anonymous
 5 years ago
Records show that a child of parents with heart disease has a probability of 5/6 of inheriting the disease. Assuming independence, what is the probability that, for a couple with heart disease that have two children:
(a) Both children have heart disease:
(b) Exactly one child had heart disease
Answers should be exact (a common fraction as an answer is allowed.).
anonymous
 5 years ago
Records show that a child of parents with heart disease has a probability of 5/6 of inheriting the disease. Assuming independence, what is the probability that, for a couple with heart disease that have two children: (a) Both children have heart disease: (b) Exactly one child had heart disease Answers should be exact (a common fraction as an answer is allowed.).

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Since they are independent, there is a \(\frac{5}{6}\) chance the first child will have the disease, and then the same chance the second one will have it. What's the chance that both of these will occur together?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it would be easier to use a punnett square

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Quick hint: intuition should tell you the chance they both have the disease should be smaller than the chance either alone has it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a. P(Both have heart disease) = (5/6)(5/6) b. P(Exactly one has heart disease) = P(A and not B) + P(Not A and B) = (5/6)(1/6) + (1/6)(5/6)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there was one part of the question i forget c. neither child have diesease
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