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anonymous
 5 years ago
Please help.. I need to find the area of the shaded regions. could you please show me how you get the answer so i know how to
anonymous
 5 years ago
Please help.. I need to find the area of the shaded regions. could you please show me how you get the answer so i know how to

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the area of a sector as in #26 is given by the formula (radian angle) times r^2 divided by 2. You have 2 different "radiuses" in #26 so we just take the larger area with radius (R) and subtract the inner/smaller area with radius (r) from it and your left with the shaded area. What are the Radiusesses involved in #26?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Diameter is 8; radius is half of that = 4; inner radius is 4. Add 2 to that to get 6 for the outer radius. Does this make sense so far?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0good; the shaded area is actually the area of half of a circle. if that makes sense; radian measurement is pi. Outer area  inner area = shaded area 6^2pi/2  4^2pi/2 = ShA 36pi/2  16pi/2 = ShA 18pi  8pi = ShA 10pi is the area of the shaded region of #26.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes; 10*pi should be the area of the shaded portion in #26

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if we are going to use 3.14 to equal pi; then you are correct.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0#27 seems to be missing a measurement. the inner shading is 1 cm radius; and the total outer is 7 cm radius; but what would the radius be for the middle section?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I cant see a way to figure it out with those measurements alone. maybe im missing something... lets try #28

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that is the area of the isoTriangle  the area of the inner circle, just gotta recall how to find area of the isoTriangle..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the triangle should have an area of: 21 + 7sqrt(3)/2 and we subtract 36pi from it to get the shaded area.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0are there any "multiple choice" answers to choose from?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.027.06217782  36pi does not seem correct....gonna have to try again :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I get 73.96 as long as I did it right :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and I get: 36pi  18pi  18 18pi 18 18(pi 1) 18(2.14) = 38.52 thats the best I can do fer ya :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0#29...but I gotta recalculate.. it should end up being: 18(pi  2) 18(1.14) = 20.52 I lost track of one of my sectors :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.06*6 = 36; thats a square area; pi(36)/4 = 9pi = 1 sector pi(36)/4 = 9pi = another sector both sectors together are 18pi. 36pi  18pi  36 18pi  36 18(pi  2) 18(1.14) = 20.52

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats all I can help you with; hope it helps :)
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