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anonymous
 5 years ago
What is the complete factorization of 328z^2? A.8(2+z)(2z) B.8(2+z)(2z) C. 8(2+z)^2 D.8(2z)^2
anonymous
 5 years ago
What is the complete factorization of 328z^2? A.8(2+z)(2z) B.8(2+z)(2z) C. 8(2+z)^2 D.8(2z)^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you THINK we would do in this case to start the problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you were to divide, that would change the value of the whole problem right? For example, if i were to have a problem 126 , and i divide it by 6, it wouldnt be the same as 21 would it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Exactly, so here its asking to factor. But you had the right idea, 8 can go into 32 4 times. The problem is 328z^2. If I was to take that, and put it in the form, 8(4  z^2) would it be the same problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Because when you divie you are going to get 4 and then you square it..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Take this example: 6(4+x) and expand it. What do you get?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, let me explain factoring. When we get a problem like 6(4+x) the x is a variable, meaning, the x is an unknown number. in this case, we're not trying to find x. We're just trying to rewrite that expression. 6(4+x) means 6*4 + 6*x which means 24 + 6x. You take the 6, and multiply it by 4, then, you multiply it by x so the six multiplied by 4 gives you 24, and the 6 multiplied by x simply gives you 6x. You add those together, and you get 24+6x. Let's try another, how can you expand: 5(3+z)
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