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anonymous

  • 5 years ago

when finding a perimeter of a rectangle. if one side is the square root of 27 and the other is square root of 108. what would the exact perimeter be?

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  1. anonymous
    • 5 years ago
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    Sqrt(27) + sqrt(108) + sqrt(27) + sqrt(108) Then you need to simplify each radical Do you know who to do that? sqrt(27) = 2sqrt(3) What is sqrt(108) =

  2. anonymous
    • 5 years ago
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    i show its a decimal is that right?

  3. anonymous
    • 5 years ago
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    No.. you can't do it that way. If they want "exact" Have you been working on radicals and simplifying them?

  4. anonymous
    • 5 years ago
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    Do you know how to do a factor tree?

  5. anonymous
    • 5 years ago
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    yeah we have to find the lcd or gcf

  6. anonymous
    • 5 years ago
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    27 = 3 * 3 * 3 108 = 2 * 54 = 2 * 2 * 27 = 2 * 2 * 3 * 9 = 2 * 2 * 3 * 3 * 3 So 108= 2 * 2 * 3 * 3 *3 Doyou understand this?

  7. anonymous
    • 5 years ago
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    yeah

  8. anonymous
    • 5 years ago
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    OK the way you simplify a radical is - circle groups of two that are alike. FOr example. 27 = 3 * 3 * 3 you would circle the first two 3's and they go outside the sign with the uncircled 3 left underneath. sqrt(27) = 3sqrt(3) 108 = 2 * 2 * 3 * 3 * 3 you would circle the 2's and the 3's and there would be one 3 left over. You multiply things that come out, and multiply things that are left underneath. sqrt(108) = 6sqrt(3) So 3sqrt(3) + 6sqrt(3) + 3 sqrt(3) + 6sqrt(3) = 18sqrt(3) That is your answer...

  9. anonymous
    • 5 years ago
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    wow i really like that break down thank you

  10. anonymous
    • 5 years ago
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    You are welcome

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