anonymous
  • anonymous
when finding a perimeter of a rectangle. if one side is the square root of 27 and the other is square root of 108. what would the exact perimeter be?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Sqrt(27) + sqrt(108) + sqrt(27) + sqrt(108) Then you need to simplify each radical Do you know who to do that? sqrt(27) = 2sqrt(3) What is sqrt(108) =
anonymous
  • anonymous
i show its a decimal is that right?
anonymous
  • anonymous
No.. you can't do it that way. If they want "exact" Have you been working on radicals and simplifying them?

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anonymous
  • anonymous
Do you know how to do a factor tree?
anonymous
  • anonymous
yeah we have to find the lcd or gcf
anonymous
  • anonymous
27 = 3 * 3 * 3 108 = 2 * 54 = 2 * 2 * 27 = 2 * 2 * 3 * 9 = 2 * 2 * 3 * 3 * 3 So 108= 2 * 2 * 3 * 3 *3 Doyou understand this?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
OK the way you simplify a radical is - circle groups of two that are alike. FOr example. 27 = 3 * 3 * 3 you would circle the first two 3's and they go outside the sign with the uncircled 3 left underneath. sqrt(27) = 3sqrt(3) 108 = 2 * 2 * 3 * 3 * 3 you would circle the 2's and the 3's and there would be one 3 left over. You multiply things that come out, and multiply things that are left underneath. sqrt(108) = 6sqrt(3) So 3sqrt(3) + 6sqrt(3) + 3 sqrt(3) + 6sqrt(3) = 18sqrt(3) That is your answer...
anonymous
  • anonymous
wow i really like that break down thank you
anonymous
  • anonymous
You are welcome

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