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anonymous

  • 5 years ago

how do you find ALL the values between 0 and 2pi for cos(theta)=-0.0623??

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  1. anonymous
    • 5 years ago
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    Not sure I understand the question, but this is what I think: Take the inverse cosine==> cos^-1(-0.0623) then add 90deg or pi/2(if your problem is in radians) until you go all the way around the unit circle. So if you problem is in radians you should get 1.633,3.203,4.774, 6.345

  2. amistre64
    • 5 years ago
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    you take the cosine inverse to determine the angle. Which will spit out an angle in the top half of the circle; swing down to get the other one...

  3. anonymous
    • 5 years ago
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    when i take the inverse cos, i get 93.... which is not between 0 and 2pi

  4. anonymous
    • 5 years ago
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    your calculator is in degrees, need to change it to radians

  5. anonymous
    • 5 years ago
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    yah.. duh! thanks!

  6. anonymous
    • 5 years ago
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    Oh, amistre64 is right, you should add 180deg (pi) not pi/2...sorry just saw that, you should get 1.633 and 4.774 only, my bad

  7. anonymous
    • 5 years ago
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    ya. thanks

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