math007
  • math007
This is my equation for a non homogeneous equation: y"-2y'-3y=3e^2x
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Solve the homogeneous equation using\[y=e^{\lambda x}\]to get a characteristic equation. Solve for lambda and your solution to that part will be \[y=c_1e^{\lambda_1 x}+c_2e^{\lambda_2 x}\]Then try a particular solution of the form Ae^(2x) or so...you can play around with it. Can't spend much time on it - sorry. I'll check back later if I have time.

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