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LaddiusMaximus
 5 years ago
(sinx/1+cosx)+(1+cosx/sinx)=2cscx
LaddiusMaximus
 5 years ago
(sinx/1+cosx)+(1+cosx/sinx)=2cscx

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0try to combine the fractions

LaddiusMaximus
 5 years ago
Best ResponseYou've already chosen the best response.0I was doing that. but It keeps telling me its wrong

LaddiusMaximus
 5 years ago
Best ResponseYou've already chosen the best response.0which one should be the common denominator?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0is that suppose to be sinx/(1+cosx)+(1+cosx)/sinx

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0to find a common denominator multiply the first fraction by sinx/sinx and the second fraction by (1+cosx)/(1+cosx)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think the common denominator would be (1+cosx)(sinx)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so now you have [(sin)^2+1+2cosx+(cosx)^2]/[sinx(1+cosx)]=[1+1+2cosx]/[sinx(1+cosx)]=2(1+cosx)/[sinx(1+cosx)]=2/sinx=2cscx
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