LaddiusMaximus
  • LaddiusMaximus
(sinx/1+cosx)+(1+cosx/sinx)=2cscx
Mathematics
chestercat
  • chestercat
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myininaya
  • myininaya
try to combine the fractions
LaddiusMaximus
  • LaddiusMaximus
I was doing that. but It keeps telling me its wrong
LaddiusMaximus
  • LaddiusMaximus
which one should be the common denominator?

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LaddiusMaximus
  • LaddiusMaximus
the sinx?
myininaya
  • myininaya
is that suppose to be sinx/(1+cosx)+(1+cosx)/sinx
myininaya
  • myininaya
to find a common denominator multiply the first fraction by sinx/sinx and the second fraction by (1+cosx)/(1+cosx)
anonymous
  • anonymous
I think the common denominator would be (1+cosx)(sinx)
myininaya
  • myininaya
so now you have [(sin)^2+1+2cosx+(cosx)^2]/[sinx(1+cosx)]=[1+1+2cosx]/[sinx(1+cosx)]=2(1+cosx)/[sinx(1+cosx)]=2/sinx=2cscx
LaddiusMaximus
  • LaddiusMaximus
wait, what?
LaddiusMaximus
  • LaddiusMaximus
im lost

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