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anonymous
 5 years ago
a_n= (1)^n (n+4/n+1), determine whether the sequence converges or diverges
anonymous
 5 years ago
a_n= (1)^n (n+4/n+1), determine whether the sequence converges or diverges

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did u get that lol?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use absolute after that limit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can u explain a little further

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let f(x)= a(n)= (1)^n (n+4/n+1) f(x)= lim (1)^n (n+4/n+1) > lim 1^n(n+4/n+1) = 1 \[\neq\] 0, means divergent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, alternating series test:\[\sum_{n=1}^{\infty}(1)^n*a_n = a_1a_2+a_3a_4+...\] converges if limit of a_n as n approaches infinity is 0. The limit is 1 as n approaches infinity in (n+4)/(n+1), which does not equal 0, hence, the series diverges.
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