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anonymous
 5 years ago
write a formula that produces the given terms of the sequence a_1= 1/8, a_2= 1/4, a_3= 1/2, a_4=1, a_5=2
anonymous
 5 years ago
write a formula that produces the given terms of the sequence a_1= 1/8, a_2= 1/4, a_3= 1/2, a_4=1, a_5=2

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Put everything in the same pants...like denominators: +1/8 2/8 +4/8 8/8 +16/8 .... does this help?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = 2(x)/8 ? nope.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0umm...it needs to be written in "n" form lol i think....its an infinite sequence i know that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah.... I need to learn them better. But, I can write a program that will spit out the numbers in that sequence :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, that'd be great :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ack!!.... maybe I cant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[a_n = (1)^n*2^n*1/8\] I felt SO relieved after I got this. :P Btw, it starts at n=0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i thought it started at 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, if it starts with a_1 then it should be:\[a_n = (1)^{n1}*2^{n1}*1/8\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Are we allowed to use trig? I had considered 2^n cos(pi(n1)) / 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That doesn't quite work, the first term gives you something that isn't 1/8, but yours is very creative...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0granted, but if the sequence starts at a_1 it could work...maybe....with a little luck :) and thanx!
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