anonymous
  • anonymous
write a formula that produces the given terms of the sequence a_1= 1/8, a_2= -1/4, a_3= 1/2, a_4=-1, a_5=2
Mathematics
schrodinger
  • schrodinger
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amistre64
  • amistre64
Put everything in the same pants...like denominators: +1/8 -2/8 +4/8 -8/8 +16/8 .... does this help?
amistre64
  • amistre64
y = -2(-x)/8 ? nope.....
anonymous
  • anonymous
umm...it needs to be written in "n" form lol i think....its an infinite sequence i know that

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amistre64
  • amistre64
yeah.... I need to learn them better. But, I can write a program that will spit out the numbers in that sequence :)
anonymous
  • anonymous
ok, that'd be great :)
amistre64
  • amistre64
ack!!.... maybe I cant
anonymous
  • anonymous
\[a_n = (-1)^n*2^n*1/8\] I felt SO relieved after I got this. :P Btw, it starts at n=0.
anonymous
  • anonymous
i thought it started at 1
anonymous
  • anonymous
i get it now :)
anonymous
  • anonymous
Sorry, if it starts with a_1 then it should be:\[a_n = (-1)^{n-1}*2^{n-1}*1/8\]
amistre64
  • amistre64
Are we allowed to use trig? I had considered 2^n cos(pi(n-1)) / 8
anonymous
  • anonymous
That doesn't quite work, the first term gives you something that isn't 1/8, but yours is very creative...
amistre64
  • amistre64
granted, but if the sequence starts at a_1 it could work...maybe....with a little luck :) and thanx!

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