## anonymous 5 years ago Consider the differential equation: (1+x^2)y"-6y=0

1. anonymous

show that the general solution can be written as:$y(x)=C _{1}(x+x ^{3})+C _{2}\sum_{ n=0 }^{ \infty} [((-1)^{n}x ^{2n})/((2n-1)(2n-3))]$ $C _{1}, C _{2} \rightarrow arbitrary constants$

2. anonymous

please. any1 help me with this..

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