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anonymous

  • 5 years ago

∫[e^(3t)sin(3t),dt]= ;limit(0,π)

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  1. myininaya
    • 5 years ago
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    you will definitely need to use integration by parts

  2. myininaya
    • 5 years ago
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    if you know the product rule, you can derive the formula for integration by parts

  3. myininaya
    • 5 years ago
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    if you don't know the product rule, you can use the definition of derivative to find the formual for the product rule

  4. anonymous
    • 5 years ago
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    Integrate by parts, setting e^(3x) equal to u and the trig function equal to v' each time. The 3's will cancel out every time, and you'll end up in the third term with the original integral; add it to the left and divide by two, you'll end up getting\[e^{3t}*1/6*(\sin(3t)-\cos(3t)).\] Evaluate it at the limits and out pops the value. :P

  5. anonymous
    • 5 years ago
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    that is the exact ans I got when I integrated it, QuantumModulus.....But my final ans was -1/6(1+e^3pi)

  6. anonymous
    • 5 years ago
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    Thenk you!

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