anonymous
  • anonymous
∫[e^(3t)sin(3t),dt]= ;limit(0,π)
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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myininaya
  • myininaya
you will definitely need to use integration by parts
myininaya
  • myininaya
if you know the product rule, you can derive the formula for integration by parts
myininaya
  • myininaya
if you don't know the product rule, you can use the definition of derivative to find the formual for the product rule

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anonymous
  • anonymous
Integrate by parts, setting e^(3x) equal to u and the trig function equal to v' each time. The 3's will cancel out every time, and you'll end up in the third term with the original integral; add it to the left and divide by two, you'll end up getting\[e^{3t}*1/6*(\sin(3t)-\cos(3t)).\] Evaluate it at the limits and out pops the value. :P
anonymous
  • anonymous
that is the exact ans I got when I integrated it, QuantumModulus.....But my final ans was -1/6(1+e^3pi)
anonymous
  • anonymous
Thenk you!

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