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anonymous

  • 5 years ago

Identity problem #2: sin^3 - 8/sin - 2 = sin^2 + 2sin + 4

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  1. anonymous
    • 5 years ago
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    sin^4-8-2sin=sin^2+2sin+4.....

  2. anonymous
    • 5 years ago
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    subtract

  3. anonymous
    • 5 years ago
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    wait....nevermind these are proofs not equations...give me a minute.

  4. anonymous
    • 5 years ago
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    Okay, take your time. XD

  5. anonymous
    • 5 years ago
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    this is a tough one......

  6. anonymous
    • 5 years ago
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    they are fun though..give a minute....

  7. amistre64
    • 5 years ago
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    sin^3 - 8 -------- = sin^2 + 2sin + 4 ?? is this right? sin - 2

  8. amistre64
    • 5 years ago
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    the top is a difference of cubes.....

  9. amistre64
    • 5 years ago
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    (sin-2) (sin^2 +2sin +4) ------------------- (sin-2)

  10. anonymous
    • 5 years ago
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    really? i dont see that?

  11. amistre64
    • 5 years ago
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    sin^3 - 2^3.... plain as day :)

  12. anonymous
    • 5 years ago
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    yeah, but what about 1/sin?

  13. amistre64
    • 5 years ago
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    there is no 1/sin.... which problem you doin? :)

  14. anonymous
    • 5 years ago
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    same one, 8/sin

  15. amistre64
    • 5 years ago
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    nah.... that aint it.....

  16. amistre64
    • 5 years ago
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    (sin^3 - 8)/(sin - 2) = sin^2 + 2sin + 4

  17. anonymous
    • 5 years ago
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    there are no parentheses in the problem, so im assuming that it means -8/sin

  18. amistre64
    • 5 years ago
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    then it aint gonna work out :) Have a crack at it, but its futile.....

  19. anonymous
    • 5 years ago
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    It's (sin^3 - 8)/(sin-2)

  20. anonymous
    • 5 years ago
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    oh.....ok. You were right. My bad. sorry.

  21. amistre64
    • 5 years ago
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    'sok :) Blame it on the rain :)

  22. anonymous
    • 5 years ago
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    cool.

  23. anonymous
    • 5 years ago
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    How does a difference of cubes work? Can you show me it in detail?

  24. amistre64
    • 5 years ago
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    The best way to understand it is to actually multiply a cubed expression like (a-b)^3

  25. amistre64
    • 5 years ago
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    Which of course is just (a-b)^2 times (a-b)

  26. amistre64
    • 5 years ago
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    Ack!!...splained it wrong lol (a-b)(a^2 + ab + b^2)

  27. amistre64
    • 5 years ago
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    suppose you have an expression like this (f = first and l = last): (f^3 - l^3) can be factored: (f-l)(f^2 +fl +l^2)

  28. anonymous
    • 5 years ago
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    So what would be a and b? I'm sorry, I'm no good at this stuff. Thanks for helping though!

  29. amistre64
    • 5 years ago
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    Lets use some numbers: x^2 - 64 is a good example: 4*4*4 = 64 = 4^3 x^3 - 4^3 can be factored like this: (x-4)(x^2 +4x + 4^2)

  30. amistre64
    • 5 years ago
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    that should have been x^3 - 64....

  31. amistre64
    • 5 years ago
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    many centuries ago, mathmatickers noticed patterns in the way certain forms worked; and they surmised these tricks to help them solve the stuff quicker....

  32. anonymous
    • 5 years ago
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    Wow, I get it now! Thanks soooo much!!

  33. amistre64
    • 5 years ago
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    good job... I gotta be going home now.... Ciao :)

  34. anonymous
    • 5 years ago
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    Night!

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