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sstarica, isn't this the same thing we were tackling

now find V' which is :\[V' = 2\pi rr'h'\]

now we have:
h' = 0.2 ft/sec
we need to find r'

do i just plug in

yes :)
but we need to find r' now

\[V' = 2 \pi rr' h'\]
we have h' , but we need to find r' to calculate V' = rate of volume increase

how do i do that? :(

hold on :)

thx

you need to find a relationship between r and h
so r/h = r'/h'

thats where im having problem for all the problems

cross mulitply and you'll get:
r' = rh'/r

sorry! wait you'll get:
r' = rh'/h :)

are you with me soo far?

yes :)

now plug :
r =3 ft
h = 6ft
h' = 0.2ft/sec
r' = (3)(0.2)/6
= 0.1 ft/sec

Correct me if I'm wrong please

OMG this makes so much sense now

but the website marked it wrong :(

why?

I guess there's a mistake, but that's the idea, maybe in calculation?

ok

did you get the idea?

one qquestion

sure :)

where did u get \[V \prime = 2\pi r r \prime h \prime \]

you derive with respect to r and h :)

oooooh...im sorry can u show me one more problem

so what is the given?

uhhuh

so when exactly do i start pluging in numbers?

right now, after you find the derived formula, start pluggingthe numbers :)

okay ...these are pretty simple compared to the ones i have on hw :'(

Lol, when you understand the small idea, you'll be able to figure out the bigger idea :)

did you understand my problem?

yes but how would i approach towards a hemisphere problem

to fully*

^_^

ok :)

good luck !
You're a smart student, you can figure it out :)

lol..thx

np :)
Give it a try once more. ^_^